How to set continue function?

What the function that i need to set code-step which will decide wheter my coding continue to run or stop.

i want create a code after rows named 'checkperiod'. If the result of checkperiod is true(1), i want it to stop my running code and send me a message "Make the structure bigger" and this message can be string-variable. If the resut of checkperiod is false(0), then let it continue but still send me the message by string variable that contains "fullfill".

Thank for attention

[Dyuman Joshi]

The use of logical() in line 157 is redudant. You can remove it.

Also, you can use deal to assign (the same) inputs to different outputs.

Answer 1

[Aquatris]

You are looking for assert() function.

When you condition is satsified

assert(1>0,'STOPPED THE CODE!')
fprintf('Code continues!')

Code continues!

When your condition is not satisfied;

assert(1<0,'STOPPED THE CODE!')

Error using assert
STOPPED THE CODE!

fprintf('Code continues!')

[Arif]

Will the function let my code stop/continue? It seems only give a warning message

[Steven Lord]

The warning function issues warnings that will not stop execution of your code.

The assert function and the error function throw errors that will stop execution if they are not caught by a try / catch block.

If this occurs inside a loop, you may also be interested in the break and continue keywords. break ends the loop and moves on to the next statement after the end that ends the loop. continue skips the rest of the current iteration and moves back to the start of the next loop iteration.

[Aquatris]

assert function stops the code, thats why you do not see the 'Code continues!' text when the assert condition is false.

[Arif]

thanks

Answer 2

[Fangjun Jiang]

doc continue

doc break

[Dyuman Joshi]

Also, doc return