How can I convert indices into a binary matrix?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello all, I have a txt file that includes list of selected items (there are 10 items in total). I am reading the file using "readmatrix". I want to create a binary (logical) matrix as in the example below but I am getting "The subscript vectors must all be of the same size." message. How can I fix it? Thanks for the help.
1,3,5 -> 1,0,1,0,1,0,0,0,0,0
1,2,3,7 -> 1,1,1,0,0,0,1,0,0,0
1,2,6,7,8 -> 1,1,0,0,0,1,1,1,0,0
1,2,3 -> 1,1,1,0,0,0,0,0,0,0
...
Réponse acceptée
Dyuman Joshi
le 18 Fév 2024
Modifié(e) : Dyuman Joshi
le 18 Fév 2024
ItemSet = readmatrix('Test.txt','NumHeaderLines',0)
tic
s = size(ItemSet);
%corresponding row values
row = repelem((1:s(1)).', 1, s(2))
%maximum value
m = max(ItemSet, [], 'all');
%subscript values
idx = [row(:) ItemSet(:)];
%check for NaN values
k = isnan(idx(:,2));
out = accumarray(idx(~k,:), 1, [s(1) m])
toc
Plus de réponses (1)
Alexander
le 18 Fév 2024
Maybe something like the following?
fid = fopen('Item.txt');
A = [];
while(~feof(fid))
syLine = fgetl(fid);
dyA = zeros(1,10);
syLine = ['[' syLine ']'];
dyLine = eval(syLine);
dyA(dyLine) = 1;
A = [A; dyA];
end
A
fclose(fid)
3 commentaires
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!