Plotting sine functions using linspace command
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Given: 
Find: Create a variable y that calculates the following function for the range of t.
The variable, t, should contain 450 data points, in the interval shown below. You should be using the linspace command for this because you are provided with the number of points in the array.
Don't forget your operators! You are calculating the value of y at each individual element of t.
Once you have your t and y vectors filled with values, plot y as a function of t. Remember that, when using the plot function, there should be 2 input arguments: the horizontal coordinates come first and the vertical come second. Try adding the following code to label your plot:
xlabel('t')
ylabel('y')
title('Plotting Sine Functions')
My Solution: I got as far as to state the following:
t = linspace(-4*pi,4*pi,450);
y = 4*t*sin*(2*t);
plot(t,y)
However I was getting an error in my y...
4 commentaires
Dyuman Joshi
le 25 Fév 2024
What exactly is your question?
Sam Chak
le 25 Fév 2024
What do you mean?
Spaceman
le 26 Fév 2024
Spaceman
le 26 Fév 2024
Réponse acceptée
Plus de réponses (1)
It says to plot y as a function of t. You can follow this example to make the plot.
You can learn more about linspace() and plot() in the documentation.
y = @(t) sin(pi*t).*(cos(pi*t)); % create y as a function of t
t = linspace(-pi/2, pi/2, 900); % use linspace to create 900 points over the range -π/2 < t < π/2
plot(t, y(t)), grid on % make the plot
2 commentaires
Spaceman
le 26 Fév 2024
Sam Chak
le 26 Fév 2024
@Kyle Weaver, It's a way of creating an anonymous function. Check out this article:
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