Why am I getting the error "Too many output arguments"?

3 vues (au cours des 30 derniers jours)
Aftab Mohammed
Aftab Mohammed le 3 Mar 2024
%initialise paramteres
A = 1.7;
k = 1.380658*(10^-23);
q = 1.6 * (10^-19);
Eg = 1.1;
Ior = 19.9693*(10^-6);
Iscr = 3.3;
ki = 1.7 * (10^-3);
ns = 40;
np = 2;
Rs = 5*(10^-5);
Rp = 5*(10^5);
Tr = 301.18;
Ta = 25;
%array error = 1;
amb = [25 40 60];
irr = [0.3 0.5 1];
%Evaluate
hold on
for i=1:3
Ipv = [];
Vpv = [];
Ppv = [];
G= irr(i);
Tc = Ta + (0.2*G) + 273.18;
Isc = (Iscr + ki*(Tc-Tr))*G;
Is = Ior * ((Tc/Tr)^3) * exp(q*Eg*(1/Tr-1/Tc)/(k*A));
I = Isc;
V = 0;
while I>0
while error>0.0001
f1= I-(np*Isc)+(np*Is)*(exp(q*((V/ns)+(I*Rs/np))/(A*k*Tc))-1)+(((V*np/ns)+(I*Rs))/(Rp));
df1= 1+(Rs/Rp)+((q*Is*Rs)/(A*k*Tc))*(exp(q*((V/ns)+(I*Rs/np))/(A*k*Tc)));
I= I-(f1/df1);
error=abs(f1/df1);
end
Ipv= [Ipv I];
Vpv = [Vpv V];
Ppv= [Ppv I*V];
V = V+0.1;
error = 1;
end
plot(Vpv, Ipv);
% plot(Vpv, Ppv);
end
Error using error
Too many output arguments.

Réponse acceptée

the cyclist
the cyclist le 3 Mar 2024
You are confusing MATLAB by using error (a MATLAB function) as a variable name.
I changed that variable name to errorVal, and initialized it to -Inf.
%initialise paramteres
A = 1.7;
k = 1.380658*(10^-23);
q = 1.6 * (10^-19);
Eg = 1.1;
Ior = 19.9693*(10^-6);
Iscr = 3.3;
ki = 1.7 * (10^-3);
ns = 40;
np = 2;
Rs = 5*(10^-5);
Rp = 5*(10^5);
Tr = 301.18;
Ta = 25;
%array error = 1;
amb = [25 40 60];
irr = [0.3 0.5 1];
%Evaluate
errorVal = -Inf;
hold on
for i=1:3
Ipv = [];
Vpv = [];
Ppv = [];
G= irr(i);
Tc = Ta + (0.2*G) + 273.18;
Isc = (Iscr + ki*(Tc-Tr))*G;
Is = Ior * ((Tc/Tr)^3) * exp(q*Eg*(1/Tr-1/Tc)/(k*A));
I = Isc;
V = 0;
while I>0
while errorVal>0.0001
f1= I-(np*Isc)+(np*Is)*(exp(q*((V/ns)+(I*Rs/np))/(A*k*Tc))-1)+(((V*np/ns)+(I*Rs))/(Rp));
df1= 1+(Rs/Rp)+((q*Is*Rs)/(A*k*Tc))*(exp(q*((V/ns)+(I*Rs/np))/(A*k*Tc)));
I= I-(f1/df1);
errorVal=abs(f1/df1);
end
Ipv= [Ipv I];
Vpv = [Vpv V];
Ppv= [Ppv I*V];
V = V+0.1;
errorVal = 1;
end
plot(Vpv, Ipv);
% plot(Vpv, Ppv);
end

Plus de réponses (2)

Torsten
Torsten le 3 Mar 2024
Modifié(e) : Torsten le 3 Mar 2024
You don't initialize "error" in your code by giving it a value before you use it in the while loop.
That's why MATLAB assumes error to be the built-in "error" command:

Walter Roberson
Walter Roberson le 3 Mar 2024
You do not initialize error before you use it.
error happens to be the name of an important Mathworks function -- a function that is not permitted to return a value and so cannot exist in a form
while error>0.0001
Best would be if you used a different variable name (and made sure to initialize it). Compromise would be if you assigned to error before you use it.

Catégories

En savoir plus sur Search Path dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by