when char(65) then A.
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but when we define A='5', then char(5) can not be the result A. how can we get this value?
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Star Strider
le 17 Avr 2015
You have defined ‘A’ as a string, so it will remain so. If you want to find the numeric value (5) you assigned to ‘A’, you would have to use the str2num or similar funcitons:
A = '5';
a = str2num(A)
produces:
a =
5.0000e+000
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