Why does MATLAB not finding a element from my matrix?

9 vues (au cours des 30 derniers jours)
Tshikaya
Tshikaya le 27 Mar 2024
Commenté : Walter Roberson le 24 Juin 2025
x = 0.4:0.01:0.5
x = 1x11
0.4000 0.4100 0.4200 0.4300 0.4400 0.4500 0.4600 0.4700 0.4800 0.4900 0.5000
idx = find(x==0.41)
idx = 1x0 empty double row vector
  3 commentaires
Tshikaya
Tshikaya le 27 Mar 2024
Thank you for the tip. My problem was actually the following:
A = zeros(1,100);
x = zeros(1,100);
for i = 1:100
x(i) = 0.01*randi([38 45],1,1);
if ismember(0.41,x(i));
A(i) = 10;
else
A(i) = -1;
end
end
So I was shoked to see that x was sometimes 0.41 but still not picking from the code. I have just changed ismember by ismembertol and now everything is fine.
Walter Roberson
Walter Roberson le 24 Juin 2025
Note that the colon operator is handled as repeated addition, so 0.4, 0.4+0.1, 0.4+0.1+0.1, 0.4+0.1+0.1+0.1 and so on. Because double precision numbers operate in binary instead of in decimal, 0.1 cannot be exactly represented, and instead each 0.1 addition adds 0.1000000000000000055511151231257827021181583404541015625
Mathworks could have chosen an impletation of (initial value) + increment * (position in the sequence minus 1), so 0.4 + [0, 1, 2, 3, 4 ...] * 0.1 ... but Mathworks did not chose that (possibly for efficiency reasons.)

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Réponse acceptée

Stephen23
Stephen23 le 27 Mar 2024
Déplacé(e) : Dyuman Joshi le 27 Mar 2024
Testing for exact equivalence of binary floating point numbers should be avoided.
Compare the values, are they actually the same? (hint: no):
x = 0.4:0.01:0.5;
fprintf('%.40f\n', x(2), 0.41)
0.4100000000000000310862446895043831318617 0.4099999999999999755750934582465561106801
The recommended approach is to compare the absolute difference against a tolerance:
tol = 1e-5;
abs(x(2)-0.41)<tol
ans = logical
1
More information on this topic:
This is worth reading as well:
  2 commentaires
Tshikaya
Tshikaya le 27 Mar 2024
Thank you for your answer
Steven Lord
Steven Lord le 24 Juin 2025
If you're using release R2024b or later, you could use the isapprox function to determine if two numbers are approximately equal.

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