Why does MATLAB not finding a element from my matrix?
9 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Tshikaya
le 27 Mar 2024
Commenté : Walter Roberson
le 24 Juin 2025
x = 0.4:0.01:0.5
idx = find(x==0.41)
3 commentaires
Walter Roberson
le 24 Juin 2025
Note that the colon operator is handled as repeated addition, so 0.4, 0.4+0.1, 0.4+0.1+0.1, 0.4+0.1+0.1+0.1 and so on. Because double precision numbers operate in binary instead of in decimal, 0.1 cannot be exactly represented, and instead each 0.1 addition adds 0.1000000000000000055511151231257827021181583404541015625
Mathworks could have chosen an impletation of (initial value) + increment * (position in the sequence minus 1), so 0.4 + [0, 1, 2, 3, 4 ...] * 0.1 ... but Mathworks did not chose that (possibly for efficiency reasons.)
Réponse acceptée
Stephen23
le 27 Mar 2024
Déplacé(e) : Dyuman Joshi
le 27 Mar 2024
Testing for exact equivalence of binary floating point numbers should be avoided.
Compare the values, are they actually the same? (hint: no):
x = 0.4:0.01:0.5;
fprintf('%.40f\n', x(2), 0.41)
The recommended approach is to compare the absolute difference against a tolerance:
tol = 1e-5;
abs(x(2)-0.41)<tol
More information on this topic:
This is worth reading as well:
2 commentaires
Steven Lord
le 24 Juin 2025
If you're using release R2024b or later, you could use the isapprox function to determine if two numbers are approximately equal.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!