How do I fix this error?

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Byungho
Byungho le 4 Avr 2024
Commenté : Walter Roberson le 25 Août 2024
deltat=0.1;
nsamples=2^10;
fs=1/deltat;
time=[0 : deltat : deltat*(nsamples-1)];
psdtot(1:nsamples/2+1) = zeros(1,nsamples/2+1);
nblock = 10;
for k=1:nblock
for i=1: nsamples
ydata(i,:) =5+10*cos(2*pi*time+pi/6)+15* randn(1);
end
[pxx,f] = periodogram(ydata,rectwin(nsamples),nsamples,fs);
size(psdtot)
size(pxx)
psdtot = psdtot + pxx/nblock;
end
ans = 1x2
1 513
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ans = 1x2
513 1024
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Arrays have incompatible sizes for this operation.
figure(1);
plot(time,ydata);
I'm trying to generate Gaussian noise from x(t)=5+10*cos(2*pi*t+pi/6)+G(sigma,t)
G(sigma,t) is Gaussian noise with a standard deviation of 15 (sigma G=15), detat=0.1(s), and nsample=2^10.
It is the start of calculating Power Spectral Density with FFT.
The overall variance of the signal is (sigma g)^2+(A)^2/2 as expected.
The generated random signal should be sinusoidal because X(t) has the cosine factor.
  1 commentaire
Torsten
Torsten le 4 Avr 2024
You cannot add arrays of size 1x513 and 513x1024 (see above).

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cui,xingxing
cui,xingxing le 5 Avr 2024
Modifié(e) : cui,xingxing le 27 Avr 2024
You should make sure that the array dimensions in the arithmetic are consistent, for example I changed your psdtot variable to a column vector. As far as I remember, matlab supports automatic dimension expansion since R2016a/b.
deltat=0.1;
nsamples=2^10;
fs=1/deltat;
time=[0 : deltat : deltat*(nsamples-1)];
psdtot(1:nsamples/2+1) = zeros(1,nsamples/2+1);
psdtot = psdtot(:); % here
nblock = 10;
for k=1:nblock
for i=1: nsamples
ydata(i,:) =5+10*cos(2*pi*time+pi/6)+15* randn(1);
end
[pxx,f] = periodogram(ydata,rectwin(nsamples),nsamples,fs);
psdtot = psdtot + pxx/nblock;
end
figure(1);
plot(time,ydata);
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  1 commentaire
Derek
Derek le 9 Avr 2024
Modifié(e) : Derek le 9 Avr 2024
So using this data provided how do you plot the psd vs frequency? In a log log plot. Do you have to do the fgts prior to the peridogram

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Jose Sevilla
Jose Sevilla le 25 Août 2024
Hola todos necesito ayuda con este gramento de codigo en Matlab 2024RA
% Inicialización de variables
distances = distance_start:distance_increment:distance_end;
Unrecognized function or variable 'distance_start'.
received_power_5 = zeros(1, num_measurements); % 5to piso
received_power_4 = zeros(1, num_measurements); % 4to piso
received_power_3 = zeros(1, num_measurements); % 3er piso
std_dev_5 = zeros(1, num_measurements); % Desviación estándar 5to piso
std_dev_4 = zeros(1, num_measurements); % Desviación estándar 4to piso
std_dev_3 = zeros(1, num_measurements); % Desviación estándar 3er piso
rmse = zeros(1, num_measurements); % Error medio cuadrático
k_factor = zeros(1, num_measurements); % Factor K
  1 commentaire
Walter Roberson
Walter Roberson le 25 Août 2024
That code has the potential to work provided that
num_measurements = length(distances);
But if num_measurements is different than distances, then it seems most likely that you need more like
% Inicialización de variables
distances = (distance_start:distance_increment:distance_end).';
num_distances = length(distances);
received_power_5 = zeros(num_distances, num_measurements); % 5to piso
received_power_4 = zeros(num_distances, num_measurements); % 4to piso
received_power_3 = zeros(num_distances, num_measurements); % 3er piso
std_dev_5 = zeros(num_distances, num_measurements); % Desviación estándar 5to piso
std_dev_4 = zeros(num_distances, num_measurements); % Desviación estándar 4to piso
std_dev_3 = zeros(num_distances, num_measurements); % Desviación estándar 3er piso
rmse = zeros(num_distances, num_measurements); % Error medio cuadrático
k_factor = zeros(num_distances, num_measurements); % Factor K

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