I have a code in python and want to convert it in matlab format

def DEM(Km, Gm, Ki, Gi, alphai, phii, phi0=0.0, r=1000, phitol=1.0E-10, gamma=0.01):
phi = np.sum(phii)
fraci = phii / np.sum(phi)
ci = fraci * alphai / r
n = int(np.ceil((np.log(1.0 - phi) - np.log(1.0 - phi0)) / np.sum(np.log(1.0 - ci))))
m = len(alphai)
def func(r):
f = np.empty(m)
f[0] = np.log(alphai[0] / r[0]) + np.log(1.0 - phi0 / phi) - np.log(
1 - ((1.0 - phi) / (1.0 - phi0)) ** (1.0 / n))
for j in range(1, m):
f[j] = f[j - 1] + np.log(alphai[j] / r[j]) + np.log(r[j - 1] / alphai[j - 1] - fraci[j - 1])
return f
def fprime(r):
jac = np.diag(-1.0 / r)
for j in range(0, m - 1):
jac[j + 1:, j] = -1.0 / r[j] + 1.0 / (r[j] - fraci[j] * alphai[j])
return jac
r0 = r * np.ones(m)
ri = fsolve(func, r0, fprime=fprime, factor=0.1)
ci = fraci * alphai / ri
thetai = theta(alphai)
fi = f(alphai, thetai)
K = np.empty(n)
G = np.empty(n)
phi = np.empty(n)
K_ = Km
G_ = Gm
phi_ = phi0
for i in range(n):
dphi = ci[0] * (1.0 - phi_)
K_, G_ = KG(K_, G_, Ki[0], Gi[0], ci[0], thetai[0], fi[0])
phi_ += dphi
for j in range(1, m):
dphi *= ci[j] * (1.0 - ci[j - 1]) / ci[j - 1]
K_, G_ = KG(K_, G_, Ki[j], Gi[j], ci[j], thetai[j], fi[j])
phi_ += dphi
K[i] = K_
G[i] = G_
phi[i] = phi_
return K, G, phi

Réponses (1)

Steven Lord
Steven Lord le 15 Avr 2024
Do you need to convert the code or would being able to run the code in MATLAB be sufficient? If the latter, see the documentation for instructions on how to run Python code in MATLAB.

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Version

R2023a

Question posée :

le 15 Avr 2024

Modifié(e) :

le 16 Avr 2024

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