Effacer les filtres
Effacer les filtres

How to make correct Regex?

4 vues (au cours des 30 derniers jours)
Nicholas Kavouris
Nicholas Kavouris le 19 Avr 2024
Commenté : Voss le 19 Avr 2024
I have an output log from a system which i am looking to capture data from. The data is found in the printout in the following phrase:
"actualIntensity: Optional(8.24%)". I would like to capture the 8.24 part of this phrase.
I have been using
regexp(text,'actualIntensity: Optional\(([0-9]*\.[0-9]+)\%)','match')
But this returns the entire phrase.
How can i modify this regex to only return 8.24, without all the other text?
  1 commentaire
Dyuman Joshi
Dyuman Joshi le 19 Avr 2024
text is a built-in function. Naming variables (or scripts for that matters) using function names is not a good practice in MATLAB.
Best to change the variable name; a standard variable name in this context is txt.

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Réponses (1)

Voss
Voss le 19 Avr 2024
Use 'tokens' instead of 'match'.
  1 commentaire
Voss
Voss le 19 Avr 2024
txt = "actualIntensity: Optional(8.24%)";
% original but with 'tokens'
regexp(txt,'actualIntensity: Optional\(([0-9]*\.[0-9]+)\%)','tokens')
ans = 1x1 cell array
{["8.24"]}
% original but with 'tokens','once'
regexp(txt,'actualIntensity: Optional\(([0-9]*\.[0-9]+)\%)','tokens','once')
ans = "8.24"
% removing \ before % and combining the [0-9]
regexp(txt,'actualIntensity: Optional\(([0-9\.]+)%)','tokens','once')
ans = "8.24"
% capturing anything between ( and %) in the input string
regexp(txt,'actualIntensity: Optional\((.*)%)','tokens','once')
ans = "8.24"

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