How to Convert a Scalar Struct with Vector Fields to a Vector Struct with Scalar Fields?

I have a scalar struct S with each field a row vector of the same number of elements.

S.x = [1 2];
S.y = [10 20];

I want create a struct array, A, with same number of elements as in the fields in S, with the same field names as S, where each field value in each element of A is correspondingly indexed from the original field in S. I'm not sure I'm explaining this well.

So far I have this, which works:

C = [fieldnames(s) , arrayfun(@(c) mat2cell(c{1},1,ones(1,numel(c{1}))),struct2cell(s),'Uni',false)].';
A = struct(C{:})

a = 1x2 struct array with fields:
    x
    y

[A.x]

ans = 1x2

1 2

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[A.y]

ans = 1x2

10 20

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Open to suggestions on better (e.g., easier to understand) alternatives.

Answer 1

[Voss]

S.x = [1 2];
S.y = [10 20];

C = [fieldnames(S) , struct2cell(structfun(@num2cell,S,'Uni',false))].';
A = struct(C{:})

A = 1x2 struct array with fields:
    x
    y

[A.x]

ans = 1x2

1 2

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[A.y]

ans = 1x2

10 20

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Answer 2

[Voss]

S.x = [1 2];
S.y = [10 20];

C = [fieldnames(S) , cellfun(@num2cell,struct2cell(S),'Uni',false)].';
A = struct(C{:})

A = 1x2 struct array with fields:
    x
    y

[A.x]

ans = 1x2

1 2

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<mw-icon class=""></mw-icon>

[A.y]

ans = 1x2

10 20

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Answer 3

[Voss]

S.x = [1 2];
S.y = [10 20];

N = numel(S.x);
f = fieldnames(S);
NF = numel(f);

clear A
A(N) = S;
for ii = 1:N
    for jj = 1:NF
        A(ii).(f{jj}) = S.(f{jj})(ii);
    end
end

A

A = 1x2 struct array with fields:
    x
    y

[A.x]

ans = 1x2

1 2

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<mw-icon class=""></mw-icon>

[A.y]

ans = 1x2

10 20

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