- Plotting Issue with Cubic Spline: The line "plot(xspace2,S,'g')" seems to be incorrect because "xspace2" is used for polynomial interpolation, not for cubic spline interpolation. You probably meant to plot "xspace3" against "S" for the cubic spline part:
It is difficult to control the range
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Hellow there. I want to connect functions with different scopes, but it doesn't work. Where did I go wrong? Have a nice day everyone
here is my code
clc; clear all; close all;
A = readmatrix('w10_data.xlsx','Sheet','Sheet1');
x = A(:,1);
fx = A(:,2);
%1D linear interpolation
xspace = [];
px = [];
for i = 1:3
x_segment = linspace(x(i), x(i+1),101);
p_segment = fx(i) + (fx(i+1) - fx(i))/(x(i+1)-x(i))*(x_segment-x(i));
xspace = [xspace x_segment(1:end-1)];
px = [px p_segment(1:end-1)];
end
% Polynomial interpolation
xspace2 = 4:0.01:7;
Lx = zeros(1,length(xspace2));
for j = 1:size(x,1)
lj = 1;
for m = 1:size(x,1)
if m == j
continue
end
lj = lj .*(xspace2 -x(m))/((x(j)-x(m)));
end
Lx = Lx + fx(j)*lj;
end
% Cubic spline interpolation
xspace3 = 7:0.01:10;
S = spline(x(7:end),fx(7:end),xspace3);
%S = spline(x,fx,xspace2);
figure(1)
scatter(x,fx,'k','filled'); hold on;
plot(xspace,px,'b'); hold on;
plot(xspace2,Lx,'r'); hold on;
plot(xspace2,S,'g'); hold on;
xlim([0 12]);
ylim([0 20]);
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Réponse acceptée
Pratyush Swain
le 16 Mai 2024
From the code snippet you have provided , I can make out an observation as follows:
plot(xspace2,Lx,'r'); hold on;
% Correcting the following line
% plot(xspace2,S,'g'); hold on;
plot(xspace3,S,'g'); hold on;
% -----------------------------
After making the above change, I am getting the plot figure as follows:
Hope this is what you were looking for.
2 commentaires
Image Analyst
le 16 Mai 2024
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