create a 3D average curve from two 3D curves

4 vues (au cours des 30 derniers jours)
Alberto Acri
Alberto Acri le 31 Mai 2024
Commenté : Mathieu NOE le 31 Mai 2024
I have curves M1 and M2 composed of x nodes in space.
Is it possible to create an average curve (up to a specific height, from bottom to top - red curve) as in the figure?
load M1_and_M2.mat
figure
plot3(M1(:,1),M1(:,2),M1(:,3),'mo','Markersize',4);
hold on
plot3(M2(:,1),M2(:,2),M2(:,3),'go','Markersize',4);
hold off
axis equal
xlabel('x')
ylabel('y')
zlabel('z')
grid off

Réponse acceptée

Mathieu NOE
Mathieu NOE le 31 Mai 2024
hello Alberto and welcome back
we need to sort and remove duplictes in your data before creating a common z vector, then interpolate both x,y datas on this new reference
then as we have now a common z axis (zm indeed) , we can sum the x and y datas
the new curve is in black
load M1_and_M2.mat
x1 = M1(:,1);
y1 = M1(:,2);
z1 = M1(:,3);
x2 = M2(:,1);
y2 = M2(:,2);
z2 = M2(:,3);
% remove duplicates and sort z data
[z1,ia,ic] = unique(z1);
x1 = x1(ia);
y1 = y1(ia);
[z2,ia,ic] = unique(z2);
x2 = x2(ia);
y2 = y2(ia);
% ctreate new common z array
zmin = max([min(z1);min(z2)]);
zmax = min([max(z1);max(z2)]);
zm = linspace(zmin,zmax,200); % common z value
% interpolate x,y data
x1i = interp1(z1,x1,zm');
y1i = interp1(z1,y1,zm');
x2i = interp1(z2,x2,zm');
y2i = interp1(z2,y2,zm');
% mean curve
xm = (x1i+x2i)/2;
ym = (y1i+y2i)/2;
figure
plot3(x1,y1,z1,'mo','Markersize',4);
hold on
plot3(x2,y2,z2,'go','Markersize',4);
plot3(xm,ym,zm,'k*','Markersize',4);
hold off
axis equal
xlabel('x')
ylabel('y')
zlabel('z')
grid off
  2 commentaires
Alberto Acri
Alberto Acri le 31 Mai 2024
Thanks! :)
Mathieu NOE
Mathieu NOE le 31 Mai 2024
as always, my pleasure !

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Interpolating Gridded Data dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by