Effacer les filtres
Effacer les filtres

Info

Cette question est clôturée. Rouvrir pour modifier ou répondre.

solving equation in the time

1 vue (au cours des 30 derniers jours)
studentU
studentU le 22 Avr 2015
Clôturé : MATLAB Answer Bot le 20 Août 2021
hello,   I have a program where I try to solve this system:
cos(theta)=cos(b)*[sin(f)*sin(d)+cos(d)*cos(f)*cos(w)]+sin(b)*[cos(d)*sin(g)*cos(w)*sin(f)-cos(g)*sin(d)*cos(f)+cos(d)*sin(w)*sin(g)] and
cos (theta) = cos (b) * sin (h) -cos (A) [sin (b) * cos (h) * cos (l)] - sin (a) * [sin (l) sin (b) * cos (h)]
such as: h, f, w, d, g, l are precalculated parameters changing during time; I try to extract every time ti,'a' and 'b' such that 0.98<cos (theta)<=1, I try with "solve" function but it gives that I haven't a digital result .... i try it also with lsqnonlin, but non result... have you proposed solution?

Réponses (0)

Cette question est clôturée.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by