why does it change the number when using VPA?

why does it change the number? let alone that its not 100 digits.

clear all
s=vpa(1.316074012952492460819218901796999055160068590205822176731922658595866795197302133050743150246601931520047742334253421353091380742095,100)

s = 

1.316074012952492378047963939025066792964935302734375

Answer 1

[Stephen23]

"why does it change the number when using VPA?"

It doesn't. That "loss of digits" is completely unrelated to VPA.

The change of digits occurs because you are using a double numeric. All double numeric values are limited to around 16 digits of precision, regardless of how many digits you write. So your code is equivalent to this:

n = define some numeric value with around 16 digits of precision

s = vpa(n)

As you can see, VPA never even gets those 100+ digits, so it certainly can't display them!

The correct approach is to avoid using an intermediate double numeric, e.g.:

s = vpa('1.316074012952492460819218901796999055160068590205822176731922658595866795197302133050743150246601931520047742334253421353091380742095',100)

s = 

1.316074012952492460819218901796999055160068590205822176731922658595866795197302133050743150246601932