Matlab Matrix: Eliminating Duplicate Entries

Hello, all, thanks for reading this post.
I have a problem with a point coordinate matrix I create. I output the matrix correctly, but one of the bugs in the program I inherited is every point after point 1 is duplicated. I looks something like:
0 0 0
0 0 3.0000
0 0 3.0000
0 1.4225 4.8659
0 1.4225 4.8659
0 -1.4269 4.8520
0 -1.4269 4.8520
1.1125 2.3073 6.0264
1.1125 2.3073 6.0264
-1.1160 2.3007 6.0177
-1.1160 2.3007 6.0177
1.1086 -2.3144 6.0039
1.1086 -2.3144 6.0039
-1.1120 -2.3078 5.9953
-1.1120 -2.3078 5.9953
for 8 coordinates (and 7 connections, as this is a binary tree).
Is there a way to output a new point coordinate matrix where I have 8 rows, and no duplicate points?
Thanks
Edit: unique(A,'rows') will work in my case (because the point coordinates are exactly the same), but when I use it it outputs the coordinates in alpha-numeric order. Is there a way to output the coordinates in their original order, minus the duplicates?

 Réponse acceptée

Fangjun Jiang
Fangjun Jiang le 17 Nov 2011

0 votes

unique(A,'rows')

6 commentaires

Walter Roberson
Walter Roberson le 17 Nov 2011
Note: if the above does not work, then the duplicates might not be *exact* duplicates -- e.g., the difference between them might be on the order of 1E-15 . If that is the case, you might need a different strategy.
Brian
Brian le 17 Nov 2011
Actually, unique(A,'rows') will work in my case (because the point coordinates are exactly the same), but when I use it it outputs the coordinates in alpha-numeric order. Is there a way to output the coordinates in their original order, minus the duplicates?
Fangjun Jiang
Fangjun Jiang le 17 Nov 2011
Yes. the output of unique() is sorted. You can do this to get the original order.
a=[9 8 9 7 6 7 5 4 8];
[b,ind]=unique(a,'first');
b=a(sort(ind));
Brian
Brian le 17 Nov 2011
Thanks, I tried that but when I did it it only sorted the first column and deleted the other three (making it a 1 by 8 array, effectively deleting the y and z coordinates).
What I mean is: it turned:
0 0 0
0 0 3.0000
0 0 3.0000
0 1.4225 4.8659
0 1.4225 4.8659
0 -1.4269 4.8520
0 -1.4269 4.8520
1.1125 2.3073 6.0264
1.1125 2.3073 6.0264
-1.1160 2.3007 6.0177
-1.1160 2.3007 6.0177
1.1086 -2.3144 6.0039
1.1086 -2.3144 6.0039
-1.1120 -2.3078 5.9953
-1.1120 -2.3078 5.9953
into:
0
0
0
0
1.1125
-1.1160
1.1086
-1.1120
Which is right for the x coordinates. Is it possible to extend the sort to the entire matrix, not just the first column?
Walter Roberson
Walter Roberson le 17 Nov 2011
Using the indexing I suggested in my answer would deal with these issues much more readily...
Fangjun Jiang
Fangjun Jiang le 17 Nov 2011
It's a matter of selecting all the columns.
b=a(sort(ind),:)

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A(1:2:end,:)
This does not have the problem with comparing nearly equal quantities, but it does assume that the second row of each pair is acceptable

1 commentaire

Brian
Brian le 17 Nov 2011
Thanks, this worked exactly as I wanted to! Sorry I didn't see your comment until now, but this worked exactly as I needed it to.

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