convert string to bits and then convert bits back to strings ....

facing problem with this code..
word='hello';
wordBinary = reshape(dec2bin(word,7)',1,[]);
% note the <'> after the dec2bin, to transpose the matrix
for j=1:size(wordBinary,2)
wordOutput(1,j) = str2double(wordBinary(1,j));
end
disp(wordOutput);
for j=1:size(wordOutput,2)
s(1,j) = num2str(wordOutput(1,j));
end
t = reshape(s, length(s)/7, 7);
decimalValues = bin2dec(t);
y=char(decimalValues);
disp(y);
output is coming wrong.. please help. o/p is:J U - { please help me in this..

1 commentaire

Jurgen
Jurgen le 1 Mai 2015
Modifié(e) : Jurgen le 1 Mai 2015
I think dec2bin can not take a string...
Wordoutput is not declared before it is used.
I think reshape is not needed, because a string is 1xn sized by default.

Connectez-vous pour commenter.

Réponses (2)

Joseph Cheng
Joseph Cheng le 1 Mai 2015
Modifié(e) : Joseph Cheng le 1 Mai 2015
the issue is with your
t =reshape(s,length(s)/7,7);
it should read
t = reshape(s,length(s)/length(word),length(word));
decimalValues = bin2dec(t');
if you look at your original reshape you can see that it is basically transposed. This is because reshape does not fill in rows first then columns. Reshape takes the array and starts filling in the reshaped matrix starting from column 1 then moves to column 2 and so on.
this short example shows what is happening
x = [1 2 3 4 5 6 7 8 9 10 11 12]
reshape(x,3,4)

2 commentaires

if i am using what u said then is showing nothing as the output. it is saying that y is 7*1 char array but what are the values, i m not getting.
really i would say you don't understand what is happening and you should step through it step by step looking at each line in debug mode. since
word='hello';
wordBinary = reshape(dec2bin(word,7)',1,[]);
% note the <'> after the dec2bin, to transpose the matrix
for j=1:size(wordBinary,2)
wordOutput(1,j) = str2double(wordBinary(1,j));
end
disp(wordOutput);
for j=1:size(wordOutput,2)
s(1,j) = num2str(wordOutput(1,j));
end
t = reshape(s,length(s)/length(word),length(word));
decimalValues = bin2dec(t');
y=char(decimalValues);
disp(y');
works just fine

Connectez-vous pour commenter.

Guillaume
Guillaume le 1 Mai 2015
Modifié(e) : Guillaume le 1 Mai 2015
I'm not really sure what output you're looking for, but I would do it like this:
word = 'hello';
wordbinary = dec2bin(word', 7) - '0'
originalword = char(bin2dec(char(wordbinary + '0')))'

Catégories

Produits

Question posée :

le 1 Mai 2015

Commenté :

le 7 Mai 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by