Réponse acceptée

John D'Errico
John D'Errico le 2 Mai 2015

1 vote

This is wildly too confusing of a question. It LOOKS like you are trying to find subsequences of any given array that increment by exactly 1.
That simple requires you to find blocks of ones when you form the diff of an array. Thus...
A=[15,14,16,10,6,1,2,8,9,10];
dA = diff(A) == 1
dA =
0 0 0 0 0 1 0 1 1
So there is a subsequence of length 2 and another of length 3 in string A.
start_A = strfind([0,dA,0],[0 1])
start_A =
6 8
end_A = strfind([0,da,0],[1 0])
end_A =
7 10

1 commentaire

Thank u brother but what result u got that not my tension i select sub sequence on two numbers and in three numbers like 1,2 ,8,9 this is two sub sequence and 8,9,10 this is three sub sequence
and thank u

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