- do not do anything special for count 1: treat it like all of the others
- Output = fliplr( aaAA(1:2:end) )
hello experts...see I am executing a code....want some suggestions
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My code is
%script----------------------------------%
X= ' PPtPPPPP';
lengh=numel(X);
aaAA=estring(X);
zz=numel(aaAA);
comp_ratio=(lengh)/(zz)
%------------------------------------------
function y = estring(str)
len = numel(str);
i = 0;
count = zeros(1,len);
y=[];
while( i<len )
j=0;
count(i+1) = 1;
if(count==1)
y=[y 1];
while( true )
j = j + 1;
if( i+j+1 > len )
break;
end
if( str(i+j+1)==str(i+1) )
count(i+1) = count(i+1) + 1;
else
break;
end
end
if( count(i+1)==1 )
a=str(i+1);
length(a);
y = [y a];
i = i + 1;
else
a=str(i+1);
b=count(i+1);
y =[y a b];
i = i + b;
end
end
end
Input: PPtPPPPP
numel(Input)=8
*Output :* P tP [space at the end]
numel(Output)=5
I want this to be like Output" P t P [space] numel(output)=4
Please help me to modify the code to consider single count as character plus space
0 commentaires
Réponses (1)
Walter Roberson
le 6 Mai 2015
To achieve that output:
8 commentaires
Walter Roberson
le 8 Mai 2015
Those spaces are not really spaces. See http://uk.mathworks.com/matlabcentral/answers/215294#comment_283959
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