Linear indices from colon operator

3 vues (au cours des 30 derniers jours)
Radek
Radek le 14 Nov 2024
Modifié(e) : Stephen23 le 15 Nov 2024
Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?

Réponse acceptée

Matt J
Matt J le 14 Nov 2024
[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);

Plus de réponses (2)

Steven Lord
Steven Lord le 14 Nov 2024
See sub2ind.
  2 commentaires
Stephen23
Stephen23 le 14 Nov 2024
Modifié(e) : Stephen23 le 15 Nov 2024
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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array(p1:p2,p3:p4)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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Walter Roberson
Walter Roberson le 14 Nov 2024
sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Error using sub2ind (line 61)
Subscript arguments must be scalars or arrays of the same size.

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Catalytic
Catalytic le 14 Nov 2024
Modifié(e) : Catalytic le 14 Nov 2024
K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices
  1 commentaire
Matt J
Matt J le 14 Nov 2024
I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.

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