so i made the code but i only get the first two values then the values start to equal zeros wich shouldnt hapend.
this is the code :
x_start=0; %valeeur initial de x
x_end=1; %valeur final de x
n_nodes=20;
h=(x_end-x_start)/(n_nodes-1);
x=linspace(x_start, x_end, n_nodes);
y_RK4=zeros(1,n_nodes);
y_RK4(1)=3;
f=@(x,y) (-0.3*y+2*exp(-x));
for i=1,n_nodes-1;
k1=h*f(x(i),y_RK4(i));
k2=h*f((x(i)+(h/2)),(y_RK4(i)+(k1/2)));
k3=h*f((x(i)+(h/2)),(y_RK4(i)+(k2/2)));
k4=h*f((x(i)+h),(y_RK4(i)+k3));
y_RK4(i+1)=y_RK4(i)+(k1+(2*k2)+(2*k3)+k4)/6;
end

 Réponse acceptée

Torsten
Torsten le 25 Nov 2024

2 votes

Use
for i=1:n_nodes-1
instead of
for i=1,n_nodes-1;

3 commentaires

Aya
Aya le 25 Nov 2024
MAN THANK YOU SM i was about to cry, its such a stupid mistake cus i didnt notice it since we had four difrent functions to plot. THANK YOU SO MUUUUCH AGAIN THANKS TO YOU I WONT CRY THIS NIGHT.
Image Analyst
Image Analyst le 27 Nov 2024
If this Answer solves your original question, then could you please click the "Accept this answer" link to award the answerer with "reputation points" for their efforts in helping you? They'd appreciate it. Thanks in advance. 🙂 Note: you can only accept one answer (so pick the best one) but you can click the "Vote" icon for as many Answers as you want. Voting for an answer will also award reputation points.
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Aya
Aya le 4 Déc 2024
aha i did thanks man im new to matlab so i didnt know much :)))))

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Question posée :

Aya
le 25 Nov 2024

Commenté :

Aya
le 4 Déc 2024

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