Optional Arguments in Function as Struct Input

29 vues (au cours des 30 derniers jours)
Ingo Hermann
Ingo Hermann le 14 Jan 2025
Commenté : Ingo Hermann le 16 Jan 2025
I have a Matlab function with many optional arguments which I want to call with these arguments recursively... This is just a short example, my real code is much more complexe and I don't want to share it here... I know that this function seems kind of nonesense.
function [out] = calculateHatches(vec, args)
arguments
vec
args.Limit = 0
args.Color = 'red'
args.Time = '12:00'
% (and many more argumnts)
end
% some calculations that give me out
out = []
if args.Limit==0
for i=1:10
nargs = args;
nargs.Limit = 1;
% n arguments might change here ...
% calculateHatches(vec,'Limit',nargs.Limit,'Color',nargs.Color,'Time',nargs.Time)
nout = calculateHatches(vec,nargs)
out = [out, nout]
end
end
end
However, this won't work, is there a way to makt it work?
calculateHatches(vec,nargs)
But I have too many optional arguments that change over time of programming too much, that I don't want to write it into the code. This would mean a lot of administration work.
calculateHatches(vec,'Limit',nargs.Limit,'Color',nargs.Color,'Time',nargs.Time)

Réponse acceptée

Steven Lord
Steven Lord le 14 Jan 2025
Use the namedargs2cell function.
  3 commentaires
Stephen23
Stephen23 le 15 Jan 2025
"However, I can use eval to make it work somehow but this is not really nice ^^..."
EVAL is the opposite of nice. The MATLAB approach is to use a comma-separated list:
tmp = namedargs2cell(nargs);
out = calculateHatches(vec,tmp{:});
Ingo Hermann
Ingo Hermann le 16 Jan 2025

Thank you, that was what I was looking for!

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