Fast reorganization of cell arrays
26 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Christopher Smith
le 15 Fév 2025
Commenté : Stephen23
le 6 Avr 2025 à 4:38
I have two cell arrays which store row indices to other arrays for processing. TB is a column cell array that stores the indices for all of the "targets" that interact with "sources" in the SB column cell array. The cell index of TB corresponds to the same cell index of SB. In other words, all of the indices in TB{1} interact with all of the indices in SB{1}. I would like to out of TB all of the unique indices, then find all of the indices in SB that interact with each unique index in TB. The tricky bit is that some of the indices in TB are repeated across cells. I have included a minimum working example that does what I want. It runs quickly enough for small arrays, but becomes slow when the TB and SB arrays/cells get large. Is there a way to make this faster and more compact? Thank you for any insight!
% build the two arrays
TB = cell(3,1); % "target" array
TB{1} = [1;2;3;4;5];
TB{2} = [4;5;6];
TB{3} = [7,8,9,10];
SB = cell(3,1); % "source" array
SB{1} = (1:1:15)';
SB{2} = (16:1:30)';
SB{3} = (31:1:45)';
% build the intermediate sorted array
NTB = length(TB);
out1 = []; % intermediate array
for cnt = 1:NTB
for cnt2 = 1:length(TB{cnt})
out1 = [out1;repmat(TB{cnt}(cnt2),size(SB{cnt},1),1),SB{cnt}];
end
end
% pull out of the intermediate array the desired arrays
TB_desired = unique(out1(:,1)); % all of the unique "targets"
NTB_desired = length(TB_desired);
SB_desired = cell(NTB_desired,1);
for cnt = 1:NTB_desired
logvar = TB_desired(cnt) == out1(:,1);
SB_desired{cnt} = out1(logvar,2); % all of the "sources" that interact with each unique "target"
end
0 commentaires
Réponse acceptée
Stephen23
le 15 Fév 2025
Modifié(e) : Stephen23
le 15 Fév 2025
The timings might be similar for small arrays, but try testing on larger arrays!
tic
% Initialize target and source arrays
tgt = {[1;2;3;4;5],[4;5;6],[7,8,9,10]};
src = {(1:15).',(16:30).',(31:45).'};
% Preallocate the intermediate array for better performance
len = sum(cellfun(@numel,tgt) .* cellfun(@numel,src));
arr = zeros(len,2);
% Build the intermediate array more efficiently
idx = 1;
for ii = 1:numel(tgt)
val = tgt{ii}(:); % Ensure column vector
dat = src{ii};
% Calculate indices for current block:
num = numel(val) * numel(dat);
pos = idx:(idx+num-1);
% Create pairs using vectorized operations:
[tmp,raw] = ndgrid(val,dat);
arr(pos,:) = [tmp(:),raw(:)];
%
idx = idx + num;
end
% Create final mapping:
[tgx,~,ids] = unique(arr(:,1));
out = accumarray(ids,arr(:,2),[],@(x){x});
toc
SB_desired1 = out
Compared with your original code:
tic
% build the two arrays
TB = cell(3,1); % "target" array
TB{1} = [1;2;3;4;5];
TB{2} = [4;5;6];
TB{3} = [7,8,9,10];
SB = cell(3,1); % "source" array
SB{1} = (1:1:15)';
SB{2} = (16:1:30)';
SB{3} = (31:1:45)';
% build the intermediate sorted array
NTB = length(TB);
out1 = []; % intermediate array
for cnt = 1:NTB
for cnt2 = 1:length(TB{cnt})
out1 = [out1;repmat(TB{cnt}(cnt2),size(SB{cnt},1),1),SB{cnt}];
end
end
% pull out of the intermediate array the desired arrays
TB_desired = unique(out1(:,1)); % all of the unique "targets"
NTB_desired = length(TB_desired);
SB_desired0 = cell(NTB_desired,1);
for cnt = 1:NTB_desired
logvar = TB_desired(cnt) == out1(:,1);
SB_desired0{cnt} = out1(logvar,2); % all of the "sources" that interact with each unique "target"
end
toc
SB_desired0
isequal(SB_desired0,SB_desired1)
3 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!