How can I create multiple function handles in a for loop?

3 vues (au cours des 30 derniers jours)
Carles
Carles le 7 Mar 2025
Commenté : Carles le 10 Mar 2025
Hello to everyone!
I am trying to create multiple function handles with a for loop. For example:
mymat = 1:10;
for t = 1:length(mymat)
fun_t = (@) x^2-mymat(t)*x+mymat(t);
end
I would like to have 10 function handles like:
fun_1 = (@) x^2-1*x+1
...
fun_10 = (@) x^2-10*x+10
How can I do this? Would it be more convenient to use a matrix or an array with all the functions together?
Thank you very much and have a nice weekend!
  2 commentaires
Stephen23
Stephen23 le 7 Mar 2025
Modifié(e) : Stephen23 le 7 Mar 2025
"I would like to have 10 function handles like"
You might "like to have" them all named like that, but that would be very bad data design:
"Would it be more convenient to use a matrix or an array with all the functions together?"
Yes, it would be much more convenient. It would also be much more efficient, easier to debug, etc.
For example, use a cell array to store them:
But why are you creating lots and lots of separate functions like that, when you could create one that operates on the entire matrix at once? It seems like something that would be better implemented as one function.
What are you actually trying to achieve?
Carles
Carles le 10 Mar 2025
Modifié(e) : Carles le 10 Mar 2025
Hi Stephen. I have a histogram such as the one attached below, and I have done spline interpolation for the value of every bin at the center of it (in green).
I would like to know the area under the spline. If I have that F is the spline, then I can get the coefficients of the 3rd degree polynomials with F.coefs. However, the coefficients are defined as a matrix length(X_values)-1 x 4.
F = spline(X values, Y values);
polynoms = F.coefs;
My idea was to define length(X_values)-1 function handles to calculate afterwards the value of the integral in the whole domain, in that case:
fun_1 = @(x) polynoms(1,1)*x^3+polynoms(1,2)*x^2+polynoms(1,3)*x+polynoms(1,4)
...
fun_n = @(x) polynoms(n,1)*x^3+polynoms(n,2)*x^2+polynoms(n,3)*x+polynoms(n,4)
Area_1 = integral(fun_1, x_1, x_2)
...
Area_n = integral(fun_n, x_n, x_n+1)
sum(Area_1, ..., Area_n)
But I guess this is not the most appropiate approach. Any suggestions?

Connectez-vous pour commenter.

Réponse acceptée

Stephen23
Stephen23 le 10 Mar 2025
Modifié(e) : Stephen23 le 10 Mar 2025
"I would like to know the area under the spline... But I guess this is not the most appropiate approach. Any suggestions?"
Use FNINT and FNVAL from the Curve-Fitting toolbox. I will assume that you have defined the end points of spline to be y=0 (otherwise you need to locate the x-axis intercepts using e.g. root finding... OR otherwise define the ends of your spline in a way that suits your problem).
y = [0,rand(1,5),0];
x = 1:numel(y);
pp = spline(x,y);
fnplt(pp)
fn = fnint(pp);
A0 = fnval(fn,x(end)) - fnval(fn,x(1))
A0 = 4.2455
If you do not have the Curve-Fitting toolbox, then here are some alternative approaches:
xx = linspace(x(1),x(end), 1e4);
yy = ppval(pp,xx);
At = trapz(xx,yy)
At = 4.2455
Ai = integral(@(x) ppval(pp,x), x(1),x(end))
Ai = 4.2455
  1 commentaire
Carles
Carles le 10 Mar 2025
Yes, that was what I was actually looking for. Thank you!

Connectez-vous pour commenter.

Plus de réponses (2)

Matt J
Matt J le 7 Mar 2025
Modifié(e) : Matt J le 7 Mar 2025
The best would be to just have a matrix-valued function,
fun=@(x) x.^2-mymat(:).*x+mymat(:)
but you could make a cell array of scalar functions as well,
for t = 1:length(mymat)
c=mymat(t);
fun{t} = @(x) x^2-c*x+c;
end
  1 commentaire
Carles
Carles le 10 Mar 2025
How can I evaluate the fun{t}? Or integrate it?

Connectez-vous pour commenter.


Diego Caro
Diego Caro le 10 Mar 2025
Store your function handles in a cell array.
my_mat = 1:10;
my_handles = cell(size(my_mat));
for t = 1:length(my_mat)
my_handles{t} = @(x) x.^2 - my_mat(t).*x + my_mat(t);
end
  1 commentaire
Matt J
Matt J le 10 Mar 2025
Note that I already gave this as part of my answer 3 days ago. Also, it is not efficient to define the functions with the syntax,
@(x) x.^2 - my_mat(t).*x + my_mat(t);
because this causes the function handle to store the entire array my_mat which is not needed. It is for this reason that I extracted my_mat(t) to a separate variable,
c=mymat(t);
fun{t} = @(x) x^2-c*x+c;

Connectez-vous pour commenter.

Catégories

En savoir plus sur Spline Postprocessing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by