Unzip to a cell array, get the csv filles

3 vues (au cours des 30 derniers jours)
CSCh
CSCh le 10 Mar 2025
Réponse apportée : CSCh le 11 Mar 2025
HI I unzip a file to a cell
unzipfile =
10×1 cell array
{'2025-01-28/' }
{'2025-01-28/KBIS_V06_20250128_000621.csv'}
{'2025-01-28/KBIS_V06_20250128_001320.csv'}
{'2025-01-28/KBIS_V06_20250128_002007.csv'}
{'2025-01-28/KBIS_V06_20250128_002713.csv'}
{'2025-01-28/KBIS_V06_20250128_003412.csv'}
{'2025-01-28/KBIS_V06_20250128_004111.csv'}
{'2025-01-28/KBIS_V06_20250128_004816.csv'}
{'2025-01-28/KBIS_V06_20250128_005509.csv'}
{'2025-01-28/KBIS_V06_20250128_010208.csv'}
}
How can I get the content of the csv files? I woul like to avoid use unzip command to a folder I need a fast solution becaus I have lots of zip files containing hundrets of csv.

Réponse acceptée

Stephen23
Stephen23 le 11 Mar 2025
Modifié(e) : Stephen23 le 11 Mar 2025
"I got Error using readtable Unable to find or open '2025-01-28/'. Check the path and filename or file permissions."
You get an error because a folder is not a file, yet you are trying to call FOPEN/READTABLE on a folder (the CSV files are stored in a folder, which UNZIP returns as the first element of the output cell array). Use ISFILE or similar to ignore any folders:
P = './mysub'; % absolute/relative path to where the files are unzipped to
C = unzip('2025-03-11.zip',P) % note the first element is NOT a filename!
C = 1x4 cell array
{'./mysub/2025-03-11/'} {'./mysub/2025-03-11/KBIS_1.csv'} {'./mysub/2025-03-11/KBIS_2.csv'} {'./mysub/2025-03-11/KBIS_3.csv'}
dir(C{1})
. .. KBIS_1.csv KBIS_2.csv KBIS_3.csv
C(~cellfun(@isfile,C)) = []; % remove folder names
D = C;
for k = 1:numel(C)
F = C{k};
T = readtable(F);
D{k} = T;
end
All of the imported data is in the cell array D
D{:}
ans = 1x3 table
X Y Z _ _ _ 1 2 3
ans = 1x3 table
X Y Z _ _ _ 4 5 6
ans = 1x3 table
X Y Z _ _ _ 7 8 9
vertcat(D{:})
ans = 3x3 table
X Y Z _ _ _ 1 2 3 4 5 6 7 8 9
Depending on the existence of other files, you might also be able to use DIR.

Plus de réponses (2)

Diego Caro
Diego Caro le 10 Mar 2025
Use readmatrix for each cell. Use a for loop.

CSCh
CSCh le 11 Mar 2025
Thank you so much, Steven and Walter. Both codes work. However, I guess a more "memory-friendly" (without unpacking to folder + loop) alternative is not feasbe, right?

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R2024b

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