Cell array Filtering when using readlines

5 vues (au cours des 30 derniers jours)
Jason
Jason le 29 Avr 2025
Modifié(e) : Stephen23 le 2 Juin 2025
Hello, after I have read an array from a piece of equipment
writeline(s,command); pause(0.02);
data='N/A';
nb=s.NumBytesAvailable
data={}; ct=0;
while nb>0
ct=ct+1;
d = readline(s)
data{ct,1}=d;
end
data
I get this:
data =
884×1 cell array
{[" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21"]}
{[" 190.24 190.27 190.3 190.33 190.36 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999 -999 -999"]}
...
{[" 190.24 190.27 190.3 190.33 190.36 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999" ]}
...
{["-1.38866E-009 -999 -999 -999 -999 -999 -999" ]}
{[" -999 -999 -999" ]}
{[":"
I want to remove any line that doesn't have just -999 as all the values, so I tried modifing to this:
writeline(s,command); pause(0.02);
data='N/A';
nb=s.NumBytesAvailable
data={}; ct=0; idx=0;
while nb>0
ct=ct+1;
d = readline(s)
if d~=[" -999 -999 -999 -999 -999 -999 -999 -999"]
idx=idx+1;
data{idx,1}=d;
end
nb=s.NumBytesAvailable
end
data
and this nearly gives me what I want
data =
11×1 cell array
{[" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21"]}
{[" 190.24 190.27 190.3 190.33 190.36 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999" ]}
{[" -0.999999 -1 -1 -1 -1.00001 -1.00001 -1.00001 -1.00001"]}
{[" -1.00002 -1.00002 -1.00002 -1.00003 -1.00003 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999" ]}
{["-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" ]}
{["-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" ]}
{["-1.38866E-009 -999 -999 -999 -999 -999 -999" ]}
{[" -999 -999 -999" ]}
{[":" ]}
How can I also get rid of these line entries:
{[" -999 -999 -999 -999 -999 -999" ]}
{[" -999 -999 -999" ]}
{[":" ]}
Thanks for any help

Réponse acceptée

Stephen23
Stephen23 le 29 Avr 2025
Modifié(e) : Stephen23 le 29 Avr 2025
Do not store lots of scalar strings in a cell array, doing so makes processing them harder:
S = [" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21"; " 190.24 190.27 190.3 190.33 190.36 -999 -999 -999"; " -999 -999 -999 -999 -999 -999"; " -0.999999 -1 -1 -1 -1.00001 -1.00001 -1.00001 -1.00001"; " -1.00002 -1.00002 -1.00002 -1.00003 -1.00003 -999 -999 -999"; " -999 -999 -999 -999 -999 -999"; "-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009"; "-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009"; "-1.38866E-009 -999 -999 -999 -999 -999 -999"; " -999 -999 -999"; ":"]
S = 11x1 string array
" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21" " 190.24 190.27 190.3 190.33 190.36 -999 -999 -999" " -999 -999 -999 -999 -999 -999" " -0.999999 -1 -1 -1 -1.00001 -1.00001 -1.00001 -1.00001" " -1.00002 -1.00002 -1.00002 -1.00003 -1.00003 -999 -999 -999" " -999 -999 -999 -999 -999 -999" "-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" "-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" "-1.38866E-009 -999 -999 -999 -999 -999 -999" " -999 -999 -999" ":"
X = cellfun(@isempty,regexp(S,'^(\s+-999)+|:$','once'));
Z = S(X)
Z = 7x1 string array
" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21" " 190.24 190.27 190.3 190.33 190.36 -999 -999 -999" " -0.999999 -1 -1 -1 -1.00001 -1.00001 -1.00001 -1.00001" " -1.00002 -1.00002 -1.00002 -1.00003 -1.00003 -999 -999 -999" "-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" "-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" "-1.38866E-009 -999 -999 -999 -999 -999 -999"
  4 commentaires
Stephen23
Stephen23 le 29 Avr 2025
"I've also just realised that your S is different to my 'd'. I only get one line at a time"
I assumed that you wanted to filter the entire array after the loop. You can also apply the REGEXP to one single line of text, in which case you might want to use e.g. IF rather than indexing:
d = " 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21";
isempty(regexp(d,'^(\s+-999)+|:$','once'))
ans = logical
1
d = " -999 -999 -999 -999 -999 -999";
isempty(regexp(d,'^(\s+-999)+|:$','once'))
ans = logical
0
Jason
Jason le 29 Avr 2025
Yes thats done it, thankyou!

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Plus de réponses (1)

Star Strider
Star Strider le 29 Avr 2025
Try something like this —
% data =
% 884×1 cell array
data = { ...
{[" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21"]}
{[" 190.24 190.27 190.3 190.33 190.36 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999" ]}
{[" -0.999999 -1 -1 -1 -1.00001 -1.00001 -1.00001 -1.00001"]}
{[" -1.00002 -1.00002 -1.00002 -1.00003 -1.00003 -999 -999 -999"]}
{[" -999 -999 -999 -999 -999 -999" ]}
{["-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" ]}
{["-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009" ]}
{["-1.38866E-009 -999 -999 -999 -999 -999 -999" ]}
{[" -999 -999 -999" ]}
{[":" ]}};
% Q = cellfun(@(x) x, data, Unif=0) % See What 'cellfun' Returns
% Q{1}
% Q{end}
db = cellfun(@(x)sscanf(x{:},"%f"), data, Unif=0); % Use 'sscanf' To Convert The String Values To Numeric
Lvc = cellfun(@(x) ~all(x == -999), db, Unif=0); % Test For 'all' Values To Be -999
Lv = cell2mat(Lvc); % Convert Cell Logical Array To Logical Array
data{Lv,:} % Return Edited Cell Array
ans = 1x1 cell array
{[" 190 190.03 190.06 190.09 190.12 190.15 190.18 190.21"]}
ans = 1x1 cell array
{[" 190.24 190.27 190.3 190.33 190.36 -999 -999 -999"]}
ans = 1x1 cell array
{[" -0.999999 -1 -1 -1 -1.00001 -1.00001 -1.00001 -1.00001"]}
ans = 1x1 cell array
{[" -1.00002 -1.00002 -1.00002 -1.00003 -1.00003 -999 -999 -999"]}
ans = 1x1 cell array
{["-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009"]}
ans = 1x1 cell array
{["-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009-1.38866E-009"]}
ans = 1x1 cell array
{["-1.38866E-009 -999 -999 -999 -999 -999 -999"]}
.
  2 commentaires
Jason
Jason le 29 Avr 2025
Thankyou
Star Strider
Star Strider le 29 Avr 2025
My pleasure!

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