How can I see the solution of Modern Engineering Mathematics_6th_Edition (2020) (Complex Numbers)

I am doing my homework and see check answer using MATLAB. But I didn't see the answers any where. Please help me?

Answer 1

[Rik]

You can find guidelines for posting homework on this forum here. If you have trouble with Matlab basics you may consider doing the Onramp tutorial (which is provided for free by Mathworks). If your main issue is with understanding the underlying concept, you may consider re-reading the material you teacher provided and ask them for further clarification.

In this case, your task is to do the calculation, and to implement the very same thing in Matlab. So for 1f you would do this:

z=4+3j,w=2-j

z = 4.0000 + 3.0000i

w = 2.0000 - 1.0000i

w/z

ans = 0.2000 - 0.4000i

[Nguyen]

Thank you for your response! At first, I thought the answers would be readily available here, but now I understand that I need to ask more specific questions to get proper help. I really appreciate your guidance and will try to be clearer in future posts. Thanks again!

[Sam Chak]

Hi @Nguyen

In Q1.b, What does mean? I have not learned this. If I enter this in MATLAB, ...

w = 2 - j
w*

This statement is incomplete.

[Sam Chak]

I suspect that refers to the complex conjugate. If you enter w* literally, you will not obtain the desired result.

w = 2 - j

w = 2.0000 - 1.0000i

conj(w)

ans = 2.0000 + 1.0000i

[Sam Chak]

Q11 is slightly tricky. Basically, you need to prove that implies , or vice versa. The Symbolic Math Toolbox will be helpful for this question.

syms x y real
syms z

% Let
z = x + y*sym('1i')

z = 

% Calculate the magnitude
magnitude_z1 = abs(z + 1)

magnitude_z1 = 

magnitude_z2 = abs(z - 1)

magnitude_z2 = 

% Left hand side
lhs = magnitude_z1^2

lhs = 

% Right hand side
rhs = magnitude_z2^2

rhs = 

% Inequality
ieq = lhs > rhs

ieq = 

ieq = simplify(ieq)

ieq = 

ieq = expand(ieq)

ieq = 

ieq = simplify(ieq)

ieq =