How to multiply two matrices
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Hello,
For example I would like to multiply the following two matrices:
A = rand([10,10,10]);
B = rand([10,10,10]);
defined by:
for i=1:size(A,3)
C(:,:,i)= A(:,:,i)*B(:,:,i);
end
The question is: is this possible without the use of a for loop? Kind regards, Carlas
2 commentaires
umar siyab
le 24 Nov 2011
no its not possible without the use of loop because u have to multiply every element in the matrix with other matrix..
Jan
le 24 Nov 2011
What are the real dimensions in your problem? It matters if size(A, 3) is much larger or much smaller than size(A, 1) and size(A, 2).
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Andrei Bobrov
le 24 Nov 2011
[m n p]= size(A);
o1 = ones(p,1));
out = cell2mat(cellfun(@mtimes,mat2cell(A,m,n,o1),mat2cell(B,m,n,o1),'un',0));
ADD
[m,n,p] = size(A);
out0 = bsxfun(@times,reshape(A,m,[]),reshape(permute(B,[1 3 2]),1,[],n));
out = reshape(sum(reshape(permute(out0,[1 3 2]),m,m,n,[]),3),m,n,[]);
or for out
out = permute(blockproc(out0,[m n],@(block_struct)sum(block_struct.data,2)),[1 3 2]);
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Plus de réponses (3)
Titus Edelhofer
le 24 Nov 2011
Hi Carlas,
probably yes. But in this case probably the loop is not your worst option, as long as you initialize
C = zeros(size(A,2), size(B,1), size(A,3));
before the loop.
Titus
1 commentaire
Jan
le 24 Nov 2011
I do not completely agree with you, Titus: Instead of "not the worst" I'd claim, it is at least "very good". +1
James Tursa's MTIMESX (http://www.mathworks.com/matlabcentral/fileexchange/25977-mtimesx-fast-matrix-multiply-with-multi-dimensional-support ) can handle such tasks efficiently.
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