d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) given boundary conditions and a initial state (strange result)

2 vues (au cours des 30 derniers jours)

DDD le 2 Juin 2015

Commenté : DDD le 2 Juin 2015

It is given d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) to solve in a square 30*30 (L=30).

It is also mentioned that phi(1, y) = 1 and phi(L, y) =

DDD le 2 Juin 2015

It is not accepting the whole question

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d(phi)/dt=​laplaciano​(-phi+phi^​3-laplacia​no(phi)) given boundary conditions and a initial state (strange result)