How to make long title for a plot with automatic line breaks?
49 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I would like to use a very long title, which should have lots of line breaks, but I want to put line breaks automatically to achieve a kind of justified paragraph visually.
0 commentaires
Réponses (5)
Alberto
le 17 Juin 2015
Multiline can be done using this syntax:
figure;
str=['Line1', '\n', 'Line2'];
s=sprintf('Hello\nGoodbye');
title(s)
Micke Malmström
le 19 Fév 2018
Modifié(e) : Micke Malmström
le 19 Fév 2018
Write code to
- Get the axis width (ha.Position), and fontsize (ha.Title.FontSize) in pixels (where ha is the handle to the axis of interest)
- If you use fixed width font then it's easy to break the line with something like:
while length(ha.Title.String{end})>YourWidthValue
ha.Title.String{end:end+1}=...
{ha.Title.String{end}(1:YourWidthValue) ;...
ha.Title.String{end}(YourWidthValue:end)};
end
(have not debugged it...)
an even better way is to search backwards for the first space before your YourWidthValue...
Is it not a bit strange that matlab cannot provide this functionallity built in?
Micke Malmström
le 23 Mai 2018
ha=gca; NoCharPerLine= 78; % or whatever you want...
if ismatrix(ha(end).Title.String) && size(ha(end).Title.String,2)>NoCharPerLine
II=strfind((ha(end).Title.String(1:NoCharPerLine)),' '); % find last occurence of a space
LastSpaceIndex=II(end);
ha(end).Title.String={ha(end).Title.String(1:LastSpaceIndex-1) ;
ha(end).Title.String(LastSpaceIndex+1:end)};
end
if iscell(ha(end).Title.String)
while size(ha(end).Title.String{end},2)>NoCharPerLine
STR=ha(end).Title.String{end};
II=strfind(STR,' '); % find last occurence of a space
LastSpaceIndex=II(end);
ha(end).Title.String{end}=STR(1:LastSpaceIndex-1);
ha(end).Title.String{end+1}=STR(LastSpaceIndex+1:end);
end
end
0 commentaires
Hannes
le 15 Août 2018
Modifié(e) : Hannes
le 15 Août 2018
Thanks Micke, that helped a lot!. Now I try to adapt your code to axes labels, but struggle with that task. Do you have this already available?
2 commentaires
Micke Malmström
le 15 Août 2018
sorry, I dont have that problem with the lables...
What is your problem?
Hannes
le 15 Août 2018
The ylabel/xlabel don't have a title.string option to work with. So, I cannot just apply your code, it would need further re-coding, am I right?
Jan
le 15 Août 2018
This is a job for the textwrap command. Create an uicontrol('Style', 'text') at the wanted position and provide its handle to textwrap.
4 commentaires
Hannes
le 16 Août 2018
Thx for the response. I create a large set of subplots with many scatter plots, which are arranged in a mxn matrix, where m is the amount of input parameters and n is the amount of output parameters. I did not proceed with your approach since I hesitate to guess or somehow automate the calculation of the position for these text objects..
Jan
le 16 Août 2018
@Hannes Lück: This is a question from 2015. Prefer to open a new thread an explain your question exactly. Provide some example code to demonstrate the problem, then it is much easier to write a solution.
Voir également
Catégories
En savoir plus sur Entering Commands dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!