How to solve this differential equation?

I´m looking for dC/dx and C(x)

Parameters n, D, F, R, T, I, K are independet to x

How can I apply the one of the ode solvers to this problem with a given intial condition?

Thanks!

[RahulTandon]

the best i cud do is below!!

Answer 1

[Star Strider]

I may be missing something (if so I’ll defer to those with greater expertise if I am), the Symbolic Math Toolbox can do this easily. (You could probably do it almost as easily by hand, but then this is MATLAB Answers.)

It seems your first equation can be integrated to be a simple first-order differential equation, and although you use the partial derivative notation, both are actually ordinary differential equations. You could then substitute directly for diff(theta) in the first.

Using the Symbolic Math Toolbox, this is the code and result:

syms C(x) n D F R T I K Th(x) C0 Th0
Eq1 = diff(C,2) == diff(-n*D*(C)*F/(R*T)*diff(Th));                     % First Eqn, Integrated w.r.t. ‘x’
Eq2 = diff(Th) == -R*T/(F*K*C) * ((1/F) + K*diff(C));                   % Second Eqn
Eq3 = diff(C) == -n*D*(C)*F/(R*T)*(-R*T/(F*K*C) * ((1/F) + K*diff(C))); % Substitute Manually
C(x) = dsolve(Eq3, C(0) == C0)

C(x) =
  C0 + (D*n*x)/(F*K - D*F*K*n)

Where C0=C(0).

Solving for Th(x):

Eq4 = diff(Th) == -R*T/(F*K*C(x)) * (1/F);
Th(x) = dsolve(Eq4, Th(0) == Th0)

Th(x) =
  Th0 - (log(C0*F*K + D*n*x - C0*D*F*K*n)*(R*T - D*R*T*n))/(D*F*n) + (log(C0*F*K - C0*D*F*K*n)*(R*T - D*R*T*n))/(D*F*n)

Where Th0=Th(0).

You could easily create anonymous functions from these, or use matlabFunction to do it.

Note: I used R2015a to do this, but earlier versions should work.

Answer 2

[RahulTandon]

syms x C theta n Dee F R T I K clear; clc; str1 = '-Dee*Dy - n*Dee*C*F/(R*T)*D2theta == 0'; %wrt x str2 = 'Dtheta+R*T/F(1/(K*C)*(1/F + K*y)) == 0 '; str3 = 'y == DC'; y = dsolve(str1,str2,str3,'x')