how to move the graph vertically downward to zero?

Hi all,

In the attached graph there are 2 types of data the blue one is observed those are I want calculate the mean and shifting the graph to zero (over the red one). how can I do those calculating and shifting?

thank you in advance

Answer 1

[Star Strider]

Take the mean of the blue series and subtract it:

new_blue = blue - mean(blue(:));

Without your data I cannot get any more specific. The ‘blue’ here are the dependent variable data. Your independent variable (for example x) remains unchanged.

[lina]

this is my data script:

 dv      = datevec(obs(:,1));
 [d,~,m] = unique(dv(:,1:4),'rows');
 out     = [d,accumarray(m,obs(:,2),[],@mean)];
 out(:,6)=datenum(out(:,1),out(:,2),out(:,3),out(:,4),0,0);
 plot(out(:,6),out(:,5)*100)
 hold on
 plot(pred(:,1),pred(:,2),'r')
 datetick

[Image Analyst]

Doesn't do us much good without giving us obs also.

[lina]

Sorry for this, the beginning of my script is:

 jed = fopen('Jeddah.csv');%observed data
 rawobs=textscan(jed,'%s %f','delimiter',',','headerlines',1);%raw observed data
 fclose(jed);
 datetime=datenum(jed);
 data=[datenum(rawobs{1}),rawobs{2}];
 ds = datestr(data(:,1),'dd mmm yyyy HH:MM ss'); 
 obs=[datenum(rawobs{:,1}),rawobs{:,2}]; 
 dv      = datevec(obs(:,1));
 [d,~,m] = unique(dv(:,1:4),'rows');
 out     = [d,accumarray(m,obs(:,2),[],@mean)];
 out(:,6)=datenum(out(:,1),out(:,2),out(:,3),out(:,4),0,0);
 plot(out(:,6),out(:,5)*100)
 hold on
 plot(pred(:,1),pred(:,2),'r')
 datetick

[Image Analyst]

lina, come on. This is like a comedy of errors. Do you think we'll now be able to run this without giving us the jeddah.csv file?