solve Ax=B matrix quick help!

okay so I need help with Ax=B code where A1,A3,A5,A7 is a constant number, X1,X3,X5,X7 is a variable, and alpha is a variable. i just switched it so it looks likes this AX=alpha clc clear all

AR = 6; b = 4; theta = [pi/8 pi/4 3*pi/8 pi/2];

A = 1; n = 1:2:8 ;

for i = 1:b alpha(i) = A*sin(n(i).*theta(1))*(1+(n(i).*pi/(2.*AR*sin(theta(1))))) i = i+1 end

for i = 1:b alpha2(i) = A*sin(n(i).*theta(2))*(1+(n(i).*pi/(2.*AR*sin(theta(2))))) i = i+1 end

for i = 1:b alpha3(i) = A*sin(n(i).*theta(3))*(1+(n(i).*pi/(2.*AR*sin(theta(3))))) i = i+1 end

for i = 1:b alpha4(i) = A*sin(n(i).*theta(4))*(1+(n(i).*pi/(2.*AR*sin(theta(4))))) i = i+1 end

y = [alpha' alpha2' alpha3' alpha4'];

syms X1 X3 X5 X7 alpha

A1 = y(1,:)'

A3 = y(2,:)';

A5 = y(3,:)';

A7 = y(4,:)';

A = [A1 A3 A5 A7]

X = [X1 X3 X5 X7]'

d = A(:,1)

e = A(:,2)

f = A(:,3)

g = A(:,4)

I need to solve system of 4 system of equation. I need to so where it become X1 = A1*alpha, X2 = A3*alpha, X3 = A5 * alpha, X4 = A7*alpha

here are the results.... A =

    0.6445    2.8200    4.0841    2.2153
    0.9689    1.4925   -2.0161   -2.5397
    1.1857   -0.7080   -0.9249    2.7565
    1.2618   -1.7854    2.3090   -2.8326

X = A1 A3 A5 A7

the answer should be like... X1 = .917alpha X2 = .1104alpha anyone help me real quick please?? its just solving system of equation but with 2 unknown variables and i cant seem to conquer it