sin(2*pi) vs sind(360)
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Could someone please explain to me why sin(2*pi) gives me non-zero number and sind(360)? Does this have to do with the floating points of pi?
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Mike Croucher
le 21 Oct 2022
If you ever need to compute sin(x*pi) or cos(x*pi), its better to do sinpi(x) or cospi(x). You never explicitly multily x by a floating point approximation ot pi so you always get the results you expect.
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Stephen23
le 13 Juil 2015
Modifié(e) : Stephen23
le 13 Juil 2015
Yes, it is because π is a value that cannot be represented precisely using a finite binary floating point number. This is also shown in the sind documentation:
"Sine of 180 degrees compared to sine of π radians"
sind(180)
ans =
0
sin(pi)
ans =
1.2246e-16
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Stephen23
le 13 Juil 2015
Modifié(e) : Stephen23
le 13 Juil 2015
No.
Unless of course you buy a computer with infinite memory to hold an infinite representation of π and yet can somehow perform operations at the same speed as your current computer.
π is an irrational number. How do you imagine representing an irrational number with a finite floating point value and not getting rounding error? All numeric computations with floating point numbers include rounding errors, and it is your job to figure out how to take this into account. To understand floating point numbers you should read these:
Walter Roberson
le 13 Juil 2015
Yes, it is due to pi not being represented precisely due to the fact that floating point representation is finite.
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Torsten
le 13 Juil 2015
For a numerical computation, sin(pi)=1.2246e-16 should be exact enough.
Best wishes
Torsten.
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