Getting many outputs using blockproc
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Youssra on 18 Jul 2015
Answered: Eric Chadwick on 21 Mar 2018
I want to apply SVD for each 4*4 blocks using the "blockproc" and get 3 outputs: U, S and V so I can reconstract all blocks together again but Matlab gets me "too many ouput arguments". How can I solve this problem?
fun = @(block_struct) svd(block_struct.data);
[U S V] = blockproc(a, [4 4], fun)
This is the error that I have:
Error using blockproc
Too many output arguments.
Walter Roberson on 18 Jul 2015
No, this is not possible with blockproc().
You can use something like
function r = blocksvd(block_struct)
[U, S, V] = svd(block_struct.data);
Spad = nan(size(U));
Vpad = Spad;
Spad(1:size(S,1),1:size(S,2)) = S;
Vpad(1:size(U,1),1:size(U,2)) = U;
r = [U; Spad; Vpad];
this returns a 12 x 4 array that can be broken up again into U, S, V.
More Answers (2)
Brett Shoelson on 15 Aug 2017
Edited: Walter Roberson on 15 Aug 2017
Walter is correct that blockproc returns a single output. For clarity, though, it's worth pointing out that you can make n separate calls to blockproc, requesting args 1--n. That's tricky to do with a one-line function handle, but easy if you create a single-output function for each output that you want to generate, and call them sequentially for the image. (Not ideal, but maybe helpful.)
For instance, if you wanted to calculate the thresholdOutput of the edge(img,'LOG') function:
[~,threshOut] = edge(img,'LOG');
you could create a function called, for example, calculateEdgeThresh, with a syntax like:
function thresh = calculateEdgeThresh(img)
[~,thresh] = edge(img,'LOG');
then (in pseudo-code):
localEdgeFcn = @(x) edge(x.data,'LOG');
threshFcn = @(x) calculateEdgeThresh(x.data);
localEdge = blockproc(img,localEdgeFcn); %This one is a one-liner, via function handle
localThresh = blockproc(img,threshFcn); %This one requires the separate calculateEdgeThresh function
Image Analyst on 20 Mar 2018
Eric, blockproc() stitches it back together automatically. See my attached demos.
Eric Chadwick on 21 Mar 2018
Hello, thank you both for responding so quickly! My function does have outputs, I just did not show them when I showed my function to you. However when I went to copy and paste it just now, I realized I wasn't telling it to output the image my function normally outputs. Adding the image as an output has solved the problem.
Thank you both!
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