How to find the day number of any year from a date?

36 vues (au cours des 30 derniers jours)
Md. Golam Mostafa
Md. Golam Mostafa le 23 Juil 2015
I am very new in programming and therefore it is probably a novice's question. I have to write a script that takes a number of day(dd), month(mm) and year(yyyy)values arranged in three separate columns of a MATLAB variable and gives the day number of the year(e.g. for 03 March 2012, 31+29+3=63) as output.
  2 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 23 Juil 2015
Can you explain?
Md. Golam Mostafa
Md. Golam Mostafa le 23 Juil 2015
I have a variable in the workspace containing all the data. Column 1 stores the day(dd), column 2 month (mm) and column 3 year (yyyy). I need to find the day number (for example, for 02/01/2012 day number=2, for 03/03/2012 day number=Jan (31)+ Feb (29)+ Mar (03)=63). The day number is 63. But for 03/03/2013 day number=Jan (31)+ Feb (28)+ Mar (03)=62). I need output of each date in a separate variable.

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Réponse acceptée

Peter Perkins
Peter Perkins le 23 Juil 2015
If you are using R2014b or later, the datetime data type allows you to compute the day of year using the day function:
>> x = [2012 1 2; 2012 3 3; 2013 3 3]
x =
2012 1 2
2012 3 3
2013 3 3
>> d = datetime(x)
d =
02-Jan-2012
03-Mar-2012
03-Mar-2013
>> day(d,'dayofyear')
ans =
2
63
62
  2 commentaires
Md. Golam Mostafa
Md. Golam Mostafa le 24 Juil 2015
I am running this code but it shows an error of this kind.
??? Undefined function or method 'datetime' for input arguments of type 'double'.
Error in ==> testdaynum1 at 32 d = datetime(YMD);
What is the solution?
Peter Perkins
Peter Perkins le 24 Juil 2015
Presumably, you are not "using R2014b or later". datetime did not exist prior to that.

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Plus de réponses (3)

Andrei Bobrov
Andrei Bobrov le 24 Juil 2015
x = [2012 1 2; 2012 3 3; 2013 3 3];
d = datenum(x);
out = d - datenum(year(d),1,1) + 1;

Jos (10584)
Jos (10584) le 23 Juil 2015
help datenum
and then use simple subtraction

Sergey Kostrukov
Sergey Kostrukov le 12 Fév 2022
Modifié(e) : Sergey Kostrukov le 12 Fév 2022
Fractional value of days since biginning of the year (0-364.9999):
daysFrac = days(currentTime - datetime(year(currentTime), 1, 1, TimeZone=currentTime.TimeZone))
To get the whole number starting from 1 (i.e. day index):
floor(daysFrac + 1)

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