MATLAB doesn't recognise a string in a variable

function q = edgeindex(edgenum, indexes, id)

length_index = length(indexes);
q = cell(1,edgenum);
    b = 0;
    for i = 1:length_index
        l = indexes(i);
        if i == 1
            c = strsplit(id(l),'_');
            b = b+1;
            q{b} = l
        else
            d = strsplit(id(l),'_');
             c{3}
             d{3}
            if srtcmp(c{3},d{3})
                disp('equal')
                q{b} = [q{b} (l)]
            else
                disp('not equal')
                c = d;
                b=b+1;
                q{b} = l
            end           
        end
    end
end

Edgenum - an integer

Indexes - an array of integers

id - is a column vector made of text ex. OUT_218_46_[1][0].

At this point: c = strsplit(id(l),'_'); it gives me an error saying the first input has got to be a string. But it is a string? How do I overcome this problem?

I tried putting c = strsplit(char(id(l)),'_'); but a problem arises @ srtcmp(c{3},d{3})

Thanks in advance

[Arun Kumar]

id=OUT_218_46_[1][0];while l= 3(an integer) , id(l) gives 'T'.

[Lorenzo Chiarion Casoni]

Sorry I meant to say, it's a column vector where each element is a string. These strings would be of format - 'OUT_218_46_[1]'.

Answer 1

[Walter Roberson]

When you have a character array and you index it with a single numeric index, the result is a single character.

Column vectors of text are not considered strings: strings are row vectors of text.

Is is possible that id is a cell array of strings? If so then to extract the l'th entry you need id{l} rather than id(l) . This possibility is consistent with your error message.

[Lorenzo Chiarion Casoni]

You are right, I should change it to id{l}. But even so it gives me this error at the strcmp() - Undefined function 'srtcmp' for input arguments of type 'char'.

[Walter Roberson]

strcmp() not srtcmp()