How to find Stateflow chart using API's

18 vues (au cours des 30 derniers jours)
gvreddy
gvreddy le 28 Juil 2015
Commenté : gvreddy le 7 Août 2015
Hello All,
I have simulink model with Subsystem. My subssystem are linked with Library and these library links are resolved. Inside subsystem, I have stateflow chart. I want to find stateflow chart using m-scripts.
sflow=sfroot;
model = sflow.find('-isa', 'Simulink.BlockDiagram','-and','Name','libraryIncluded');
chartArray = model.find('-isa','Stateflow.Chart');
here chartArray = model.find('-isa','Stateflow.Chart'); does not returns statflow charts from library links. How can I get all charts from linked libraries?
PS: Please find Library file and simulink model from attachments

Réponse acceptée

Fangjun Jiang
Fangjun Jiang le 3 Août 2015
I had a similar need but couldn't find a way. It was confirmed by the Mathworks tech support that there is no direct way to find the Stateflow chart objects inside a linked library block in a model. I ended up writing the following code. It was verified in many models, including some models with nested library links.
% Updating the model is needed to make sure libraries, if any, are loaded
% There might be error updating the model, but the error are non-critical
% for this operation
try
fprintf(1,'Need to update the model to load all libraries.\n');
set_param(Model,'SimulationCommand','Update');
catch %#ok<CTCH>
fprintf(1,'There are errors updating the model. Ignore ...');
end
ChartRoots=libinfo(Model);
ChartRoots=[{Model},{ChartRoots.Library}];
sfrt=sfroot;
ChartObj=sfrt.find('-isa','Stateflow.Chart');
Index=ismember(bdroot(get(ChartObj,'Path')),ChartRoots);
ChartObj=ChartObj(Index);
  4 commentaires
Sean de Wolski
Sean de Wolski le 6 Août 2015

Welcome back Fangjun!

gvreddy
gvreddy le 7 Août 2015
Thank you Fangjun..

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Complex Logic dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by