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Get the Array Number, when value changes

16 vues (au cours des 30 derniers jours)
Marv
Marv le 29 Juil 2015
Modifié(e) : Stephen23 le 6 Oct 2015
Hello, I have the following array:
1 Monday
2 Monday
3 Monday
4 Sunday
5 Sunday
6 Friday
7 Friday
8 Friday
...
I would like to get the array number when the value changes. These are the "limits" for the values. Then I want to save these limits in new arrays, in this case:
Limits.Monday:
1
3
Limits.Sunday:
4
5
Limits.Friday
6
8
Thanks :-)
  1 commentaire
Marv
Marv le 29 Juil 2015
I forgot to mention that there could be several values with the same name, for example:
1 Monday
2 Monday
3 Monday
4 Sunday
5 Sunday
6 Monday
7 Monday
...
Is it possible to get all limits by increasing order ?
Limits.1_Monday
1
3
Limits.2_Sunday
4
5
Limits.3_Monday
6
7

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Réponses (5)

Andrei Bobrov
Andrei Bobrov le 29 Juil 2015
Modifié(e) : Andrei Bobrov le 29 Juil 2015
A = {1 'Monday'
2 'Monday'
3 'Monday'
4 'Sunday'
5 'Sunday'
6 'Friday'
7 'Friday'
8 'Friday'};
[a,~,c] = unique(A(:,2),'stable');
Limits = cell2struct(accumarray(c,cell2mat(A(:,1)),[],@(x){[min(x);max(x)]}),a,1);
add variant
A = {1 'Monday'
2 'Monday'
3 'Monday'
4 'Sunday'
5 'Sunday'
6 'Monday'
7 'Monday'
8 'Friday'};
[a,~,c] = unique(A(:,2),'stable');
i1 = [true;diff(c)~=0];
x = accumarray(cumsum(i1),cell2mat(A(:,1)),[],@(x){[min(x);max(x)]});
y = strcat(A(i1,2),{'_'},arrayfun(@(x)sprintf('%d',x),(1:nnz(i1))','un',0));
Limits = cell2struct(x,y,1);
  2 commentaires
Marv
Marv le 29 Juil 2015
I think this solutions outputs the number in the left column ? But I would like to output the array number, like:
Range_Monday=A(1:3,2)
= A(Limits.1_Monday(1,1),Limits.1_Monday(2,1))
Andrei Bobrov
Andrei Bobrov le 29 Juil 2015
See 'add variant' from my answer.

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Stephen23
Stephen23 le 29 Juil 2015
Modifié(e) : Stephen23 le 29 Juil 2015
Try this:
X = {1,'Monday';2,'Monday';3,'Monday';4,'Sunday';5,'Sunday';6,'Monday';7,'Monday'};
Y = [true;any(diff(char(X(:,2)),1,1),2);true];
idx = cumsum(Y(1:end-1));
out(:,2) = accumarray(idx,[X{:,1}],[],@(x){x([1,end])});
out(:,1) = X(Y(1:end-1),2);
and here is the output in the command window:
>> out
out =
'Monday' [2x1 double]
'Sunday' [2x1 double]
'Monday' [2x1 double]
>> out{1,2}
ans =
1
3
>> out{2,2}
ans =
4
5
>> out{3,2}
ans =
6
7
I did not put the data into a structure because while a structure with fields Monday, Tuesday, etc, makes perfect sense, placing indices in front of the names a) is not a valid variable/fieldname in MATLAB, and b) implies that the sequence order is significant, therefore an indexed container (e.g. a cell array) is more suitable.

Marv
Marv le 2 Oct 2015
Hm I still dont have the right solution.
Attached I uploaded you the data I want to analyse.
Every time the value changes, I want to get the array / column number where it changed. The output shall be a range, same as in the example above.
The problem is that there are several values with different ranges, for example: '0' is from column 1 to 57 but also from 5016 to 5110 !
So can you output the ranges chronologically please ? Like 'Range'_ChronologicNr_ArrayValue:
Range_1_0 =
[1]
[57]
Range_2_6.1029 =
[58]
[529]
Range_3_0 =
[530]
[585]
Range_4_13.0064 =
[586]
[852]
Range_5_11.0053 =
[853]
[1535]
Thanks :)
  2 commentaires
Thorsten
Thorsten le 2 Oct 2015
You forgot to attach the file.
Marv
Marv le 3 Oct 2015
Modifié(e) : Marv le 3 Oct 2015
Sorry, above is the attached file.

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Marv
Marv le 4 Oct 2015
Can someone help me ? I need a solution today :-/
  1 commentaire
Stephen23
Stephen23 le 4 Oct 2015
Modifié(e) : Stephen23 le 4 Oct 2015
The data matrix that you uploaded does not match the question. Your question states "I have the following array:"
1 Monday
2 Monday
3 Monday
4 Sunday
...
but your data file consists of a single vector of type double containing decimal values. This is a completely different format to what you question is asking about. If you want help then you need to provide clear explanations for us, and make sure that your data makes sense.
Do you want us the use your uploaded data, which has nothing to do with your question, or shall we invent some data ourselves?
You should read this, and please put into practice what it advises:

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Stephen23
Stephen23 le 4 Oct 2015
Modifié(e) : Stephen23 le 5 Oct 2015
Given your uploaded data (attached below), this code will identify the locations where the value changes:
tol = 0.01;
data = load('Log_data_Changing_Value.mat');
idx = find(diff(data.A)>tol)
and it displays these in the command window:
idx =
57
585
1535
1997
2438
4298
If you explain exactly what you need to do with these indices then we can help you to use them too.
  4 commentaires
Marv
Marv le 5 Oct 2015
Alright, so I need "data.A(idx)" to export the values ?
Stephen23
Stephen23 le 6 Oct 2015
Modifié(e) : Stephen23 le 6 Oct 2015
Correct. This is called indexing, and is a basic tool used in MATLAB for accessing data. To learn how to use indexing your should work through some of the tutorials:
And if my Answer has helped you please click on Accept.

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