display specific name on a graph with the cursor

4 vues (au cours des 30 derniers jours)
Christophe Nell
Christophe Nell le 31 Juil 2015
Commenté : Christophe Nell le 4 Août 2015
Hello, I want to be able to display the name of the dot in a graph according to the vector position.
my code is
function
fig = figure;
a = [1 2 3 4 5]
b = [2 3 4 5 6]
name{1} ='one';
name{2} ='two';
name{3}='tree';
name{4}='four';
name{5}='five';
scatter(a, b, 'filled')
dcm_obj = datacursormode(fig);
set(dcm_obj,'UpdateFcn',@myupdatefcn)
end
function txt = myupdatefcn(empt,event_obj)
pos = get(event_obj,'Position');
nameNumber = 'WantCorrectNameHere';
txt = {['X: ',num2str(pos(1))],...
['Y: ',num2str(pos(2))],...
nameNumber};
end
So I want to have access to the right name at the selected position for exemple for a(1);b(1) -> name{1}

Réponse acceptée

Jan
Jan le 31 Juil 2015
Modifié(e) : Jan le 31 Juil 2015
Perhaps the SnapToDataVertex mode is useful?
function
fig = figure;
a = [1 2 3 4 5];
b = [2 3 4 5 6];
name = {'one', 'two', 'three', 'four', 'five'};
DCM_Data.Position = [a; b];
DCM_Data.Title = name;
scatter(a, b, 'filled')
dcm_obj = datacursormode(fig);
set(dcm_obj,'UpdateFcn', {@myupdatefcn, DCM_Data});
end
function txt = myupdatefcn(empt,event_obj, DCM_Data)
pos = get(event_obj,'Position');
[dummy, index] = min(((pos(1) - DCM_Data.Position(1, :)).^2) + ...
((pos(2) - DCM_Data.Position(2, :)).^2));
nameNumber = DCM_Data.Title{index};
txt = {['X: ',num2str(pos(1))],...
['Y: ',num2str(pos(2))],...
nameNumber};
end
  2 commentaires
Christophe Nell
Christophe Nell le 4 Août 2015
Ok, thank you. I used a for loop and checked the positions of my objects compared to the cursor but this strategy is more elegant. Best
Tolga Karabiyikoglu
Tolga Karabiyikoglu le 29 Mar 2021
Thanks, Bought me out of a trouble so cheap...

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Startup and Shutdown dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by