How to find a string within a matrix and output array index to variable

First off, I hope that was titled right.

Secondly, here is my dilemma:

I have this matrix that is [1621x1] with 1-4 numbers in each row. I have a variable, called 'site' that has one of these numbers as its value.

I want to match the variable 'site',containing a number, to a number in a [1621x1] matrix and then find out what index the matching number from the [1612x1] matrix has.

I'm unclear about how to search the matrix for the specific value of 'site' and then return wherever site was found in the matrix as an index in a new variable.

I hope that I explained this right. If you need clarification, please ask!!!

Thanks!

[Cedric]

Reminds me that I had this for your previous question about sorting/copying files ;-)

 outputDir  = 'Extracted' ;
 dirContent = dir( '1p*' ) ;
 flags      = cellfun( @(s) s(25)=='r' && (s(26)=='1' ||  s(26)=='2'), {dirContent.name} ) ;
 filenames  = {dirContent(flags).name} ;
 nFiles     = numel( filenames ) ;
 for fId = 1 : nFiles
    fprintf( 'Copying file %d/%d: %s ..\n', fId, nFiles, filenames{fId} ) ;
    copyfile( filenames{fId}, fullfile( outputDir, filenames{fId} )) ;
 end

[Elena H.]

Thanks!!

Answer 1

[James Tursa]

your_matrix = 1621 x 1 matrix containing values 1 - 4
site = some value 1 - 4
indexes = find( your_matrix == site );

[Elena H.]

This gives me an error saying

Error using  == 
Matrix dimensions must agree.

Error in getsol (line 28)
indexes = find( data == site );Error using  == 
Matrix dimensions must agree.

Error in getsol (line 28)
indexes = find( data == site );

[James Tursa]

I understood that site was a scalar variable containing a value from 1 - 4. From your error this does not appear to be the case. Please state the exact sizes and classes of your variables.

[Elena H.]

site has 1-4 numbers as part of its value. It's actual value ranges from around 40-2700

[James Tursa]

You haven't answered my question. I asked for the sizes and classes of the variables involved. E.g., what does this show:

size(site)
class(site)
size(mymatrix)
class(mymatrix)

[Elena H.]

size(site)= [1  1] to [1  4] 
class(site)= double
size(data)= [1621  1]
class(data)= double

[James Tursa]

Dos this do what you want? It finds the indexes in data where the value matches any of the values present in the variable site.

indexes = find(any(bsxfun(@eq,data,site),2));

Answer 2

[Walter Roberson]

[tf, idx] = ismember(site, data);

Now where tf(K) is true, idx(K) gives an index of site(K) in data