File path containing %

I would like to get the path for directories containing % (like %MATLAB_ROOT%, %APPDATA%, etc.) in Windows. However, functions like fileparts cannot interpret the percent sign. Is there a way to make this possible within MATLAB, or the only solution is to call system commands?

Thanks, Zoli

Answer 1

[per isakson]

Use getenv, Environment variable to get values of environment variables of the underlying operating system, e.g.

>> getenv('OS')
ans =
Windows_NT
>> getenv('APPDATA')
ans =
C:\Users\poi\AppData\Roaming

%NAME% gets the value of NAME in the Command Prompt, e.g.

Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

C:\Users\poi>echo %APPDATA%
C:\Users\poi\AppData\Roaming

C:\Users\poi>

And there is the Matlab function, matlabroot

>> matlabroot
ans =
C:\Program Files\MATLAB\R2013b

[Zoltán Csáti]

I looked into getenv before, but somehow I missed it. Thank you!

[Rahul Sivagaminathan]

I have a follow up question, the getenv('APPDATA') function works if you are writing a program in matlab desktop. I want to compile my matlab program into an exe file using matlab compiler SDK. Once compiled and if i install the program in C drive then getenv('APPDATA') takes me to C\Program Files(x86) .... path but I want to go to C:\Users\poi\AppData\Roaming ... path.

So my question is - how can i get to C\Users\Username\AppData folder if my matlab exe file (compiled using matlab compiler sdk) is installed in C program files. Please help me.