I will appreciate any suggestion on this simple code. I want to substitute the elements of x >5 with 6 and x<5 with zero.
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Isaac
le 15 Août 2015
Réponse apportée : matico
le 16 Août 2015
for j=1:1:8
x=[1 2 3 4 5 6 7 8];
if x(j)>5
x(j)=subs(x(j),x(j),6);
else
x(j)=subs(x(j),x(j),0);
end
end
0 commentaires
Réponse acceptée
Azzi Abdelmalek
le 15 Août 2015
idx=x>5
x(idx)=6
x(~idx)=0
4 commentaires
Steven Lord
le 16 Août 2015
Don't define x inside your loop. It's unnecessary and is just going to waste time.
Don't use a loop; vectorize your code as Azzi suggested.
&& is intended to short-circuit when the two criteria you're trying to AND together evaluate to a scalar value. In this case, your criteria do not evaluate to scalar values. In that case, use & to perform elementwise AND.
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