creating an image using a matrix

5 vues (au cours des 30 derniers jours)
Raldi
Raldi le 8 Déc 2011
lets say we have a 50x50 matrix. All of its values are zero. I wanted to create a way to add ones only to those places of the matrix that would create a sircle if i used imshow(). So i thought if yi,yj are the coordinates for each cell i maybe could use a function like (i-yi)^2+(j-yj)^2=r^2 to find each cell that i need. Does anyone has any ideas on that or maybe a better way?

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Sven
Sven le 8 Déc 2011
Raldi, try this:
% Define the image size and where you want the circle
rows = 50;
cols = 50;
radius = 20;
center = [25 25]; % In [X,Y] coordinates
% Make the circle
[xMat,yMat] = meshgrid(1:cols,1:rows);
distFromCenter = sqrt((xMat-center(1)).^2 + (yMat-center(2)).^2);
circleMat = distFromCenter<=radius;
figure, imshow(circleMat)
UPDATE to match your comments:
% To get just the border
B = circleMat & ~bwmorph(circleMat,'erode',1);
figure, imshow(B)
  4 commentaires
Raldi
Raldi le 8 Déc 2011
ok did it thanks Sven
Sven
Sven le 8 Déc 2011
Cool, hit "accept" if it's answered then :)

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Plus de réponses (3)

Sean de Wolski
Sean de Wolski le 8 Déc 2011
Or:
r = 11; %radius
cx = 25; %xcenter
cy = 25;
sz = 50; %mat size
C = bsxfun(@(x,y)hypot(x-cx,y-cy)<=r,(1:sz)',1:sz);
imshow(C)
  1 commentaire
Raldi
Raldi le 8 Déc 2011
Thanks Sean, with a few modifications i did what i wanted.

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Andrei Bobrov
Andrei Bobrov le 8 Déc 2011
A = single(zeros(50));
A(ceil(m/2),ceil(n/2)) = 1
d = bwdist(A);
r = 20;
A(abs(d-r)<.5)=1;
imagesc(A)
  1 commentaire
Raldi
Raldi le 8 Déc 2011
thanks Andrei.

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Alex Taylor
Alex Taylor le 8 Déc 2011
The createMask method of the ROI tools was designed for the case in which you want to generate a binary image that is one where a specific ROI tool lies over an image or axes.
For example:
imshow(zeros(50));
h = imellipse(gca,[5 5 40 40]);
mask = h.createMask();
imshow(mask)
You can interactively or programmatically (as done above) any of the ROI tools, and then call the createMask method. In the case above, imellipse expects the bounding rectangle of an ellipse as the position argument. Don't know if that helps, but I thought it might be relevant to this problem.

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