How to plot a graph that consist all quadrant ?

x = -100:10:100;
y1 = 0.8*x; %L(x)
y2 = (-27/97750)*x.^3+(4/5)*x; %g(x)
y3 = (-81/9775)*x + (1726/1955)*x -(108/391); %q(x)
y4 = (27/97750)*x.^3 + (-162/1955)*x.^2 +6.6864*x -116.2103; %h(x)
y5 = -1.6*x + 120; %L2(x)
y6 = -0.012*x.^2 + 0.8*x; %f(x)

hold on;
plot(x,y1,'-r')
plot(x,y2,'-g')
plot(x,y3,'-b')
plot(x,y4,'-m')
plot(x,y5,'-y')
plot(x,y6,'-k')
legend('L(X)','g(x)','q(x)','h(x)','L2(x)','f(x)','location','northeast')
xlabel('x-axis')
ylabel('y-axis')

This is my script file, but the matlab only show the 1st and 4th quadrant of the graph!

I need all the quadrant include 2nd and 3rd in order to show the intercept of each graph.

Answer 1

[Walter Roberson]

That code does show all the quadrants. It shows x from -100 to +100 and y from -2000 to +500. 6 lines are plotted. The yellow (L plot) might be difficult to see against the background, and the q and h plots are nearly on top of each other so it can be difficult to tell the lines apart.

You might want to move the legend to southeast instead of northeast.

[Odien]

so how to adjust so that it look like this?

[Walter Roberson]

Use 'southoutside' for the location.

And use http://www.mathworks.com/matlabcentral/fileexchange/22956-axescenter

[Ashish Kulkarni]

Change your command to

legend('L(X)','g(x)','q(x)','h(x)','L2(x)','f(x)', 'location','southoutside','Orientation','horizontal')

and you'll get the legends horizontally