Why am I getting NaN using interp2?

6 vues (au cours des 30 derniers jours)
macdommy74
macdommy74 le 26 Août 2015
Commenté : macdommy74 le 26 Août 2015
  • I have a 450*90 matrix of values
  • I want to sample the matrix at 100 random sample points
However, while my interp2 function runs without errors, my output results vector contains NaN values after the 90th index.
The code below results in me getting NaN for points after the 90th index of vals - why, and how do I correct it?
Shouldn't I be able to sample 1 point from the matrix, or 50, or 100, or 1000 points?
Code:
row_vect = 1:450;
col_vect = 1:90;
[X,Y] = meshgrid(col_vect, row_vect);
V = abs(rand(450,90));
Xq = row_vect(1:100);
Yq = randi(89, 1,100);
vals = interp2(X, Y, V, Xq', Yq');
Thanks

Réponse acceptée

Torsten
Torsten le 26 Août 2015
You try to extrapolate in Y-direction.
Read the description part for interp2 under
and you'll see why you get NaN for Y-values greater 90.
Best wishes
Torsten.
  3 commentaires
Torsten
Torsten le 26 Août 2015
Use
[X,Y] = meshgrid(row_vect, col_vect);
instead of
[X,Y] = meshgrid(col_vect, row_vect);
Best wishes
Torsten.
macdommy74
macdommy74 le 26 Août 2015
I think this worked - thanks a million!!

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 26 Août 2015
Your problem is your X not your Y. max(X(:)) is 90 because your first argument to meshgrid() is col_vec which is 1:90
  1 commentaire
macdommy74
macdommy74 le 26 Août 2015
I think this worked - thanks a million!!

Connectez-vous pour commenter.

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