Is there a 2-D spline function to interpolate data and specify endpoint derivative information
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I have a set of [x,y] points representing starting, intermediate and final condition waypoints for a trajectory. I'd like to connect them using a spline, but I'd like to specify the initial derivative (initial heading) and preferably the endpoint derivative condition (final heading). Most searches provide solutions for 1-D spline functions with specified end conditions OR 2-D spline functions without the ability to specify the end conditions. To complicate, I want the initial derivative (heading, dy/dx) to be infiniti. Are there tools in the MATLAB toolbox that will help me interpolate these points with specified derivatives at the endpoints?
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Cam Salzberger
le 2 Sep 2015
Modifié(e) : Cam Salzberger
le 3 Sep 2015
Hello Clay,
I understand that you want to fit a spline to points, and also specify the slopes at the end points. You can do this with the standard spline function in MATLAB.
The standard syntax allows for fitting all of the x-y points:
% x, y - data points, xx - x-values to evaluate at, yy - y-values at those points
yy = spline(x,y,xx);
If you add values at the ends of the y input, it allows you to specify the slope at the endpoints:
yy = spline(x,[startSlope y endSlope],xx);
However, infinite values are not allowed as slope. Therefore, you have to get a little trickier and use angles as the independent variable, and both x and y values as the dependent variables. Here is a full example, with infinite slope at the start, and 0 slope at the end, along with visualization:
% Sample data (from unit circle)
x = [-1 -1/sqrt(2) 0];
y = [0 1/sqrt(2) 1];
startSlope = [-1 ; 0];
endSlope = [0 ; -1];
% Get angles of data points
[theta, ~] = cart2pol(x,y);
% Create angles to evaluate the spline at
thetaEval = linspace(pi,pi/2,1000);
% Calculate the spline
spPts = spline(theta,[startSlope [x ; y] endSlope],thetaEval);
plot(spPts(1,:),spPts(2,:),'-b',x,y,'or'); axis equal
I hope this helps with what you need.
-Cam
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Donald Yang
le 25 Déc 2021
Can you explain why the startSlope takes value [-1; 0] denotes a infinite slope? And why endSlope takes [0; -1] denotes a 0 slope?
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