how the function typecast works when convert double to uint8

I test the function typecast as follows:

 z=double(1);
 z1=typecast(z,'uint8');

and the results shows the

z1 =  0    0    0    0    0    0  240   63

As to my knowledge, each element in z1 should represent one 8-bit unsigned number. But the sum is not equal to 1.

Does anyone know how the function works and what's the meaning in vector z1?

Answer 1

[Cedric]

Look at the difference between CAST and TYPECAST, and you will understand what happens in your example.

PS: if you want to understand where these 240(F0) and 63(3F) come from, have a look a this wiki.

[Yucheng Fu]

Thank you for the help. The double format has 64 bit length. This explains exactly what happens to my case. When the typecast convert it to uint8, it should have 8 separate numbers.