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how to plot discontinuous functions in matlab?

54 vues (au cours des 30 derniers jours)
rr mm
rr mm le 6 Sep 2015
Hi everyone!
I want to plot a simple floor function without connections between points in separate steps. I do this in maple with discont=true property. I used scatter function but I want to have straight line instead of circles. how can I do the same in matlab?
thanks for your attention!

Réponses (3)

Daniel Garside
Daniel Garside le 2 Mar 2018
If you just want the visuals something like this works:
for i=1:10
plot([i, i+1],[i,i])
end

the cyclist
the cyclist le 6 Sep 2015
Here is an example that sounds like what you want:
figure
x = 1:10;
y = 3 + (x>5);
h = plot(x,y,'.');
set(h,'MarkerSize',24)
ylim([2 5])
  1 commentaire
rr mm
rr mm le 6 Sep 2015
Modifié(e) : rr mm le 6 Sep 2015
Dear friend,
it does the same scatter function, the result must be like this image.
thanks

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Walter Roberson
Walter Roberson le 6 Sep 2015
Every function sampled at a finite number of points is effectively discontinuous and there is no way to automatically tell from the finite list of sampled points whether two adjacent points "should" be joined or not.
You need to either add some intelligence about where the discontinuities are, or you need to process them symbolically by calling into MuPad's discont() function
syms x
feval(symengine, 'discont', floor(x), sym('x = 1..5'))
and then somehow process the discontinuity set in constructing your numeric plot.
If you were to work in a MuPAD notebook, you could use http://www.mathworks.com/help/symbolic/mupad_ref/plot-function2d.html as that has discontinuity processing turned on by default. I have never seen an answer for what happens if you try to feval() a MuPAD plot from the MATLAB level.

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