Effacer les filtres
Effacer les filtres

using summation and modulus?

1 vue (au cours des 30 derniers jours)
JL555
JL555 le 10 Sep 2015
Commenté : Walter Roberson le 17 Sep 2015
i think this is clearer
and that Fi(Pi) have to substituted here.

Réponses (1)

Walter Roberson
Walter Roberson le 10 Sep 2015
I am having a difficult time reading that. It is a low quality image and my eyes are having trouble.
It looks to me as if it might read
F[i](P[G,i]) = a[i]*P[G,i]^2 + b[i]*P[G,i] + c[i] + abs( conjugate(e[i]) * sin( conjugate(f[i]) * (P[G,i min] - conjugate(P[G,i])) )
where I have represented subscript by [].
Please confirm that I have the operations right. For example, why did they use implicit mulitplication for a[i]*P[G,i]^2 but explicit multiplication inside the abs() ? And the conjugate bars are displaced from where I would expect them to be. What is "PG,i min" intended to mean?
  22 commentaires
JL555
JL555 le 17 Sep 2015
Modifié(e) : JL555 le 17 Sep 2015
I just want something that in the end the result for Pi should be a 1x6 matrix. Thats the problem i dont know to code that part.
Walter Roberson
Walter Roberson le 17 Sep 2015
Go back to the code you posted above
Change the lines
ai=data(:,1);
bi=data(:,2);
ci=data(:,3);
ei=data(:,6);
fi=data(:,7);
to
ai = data(:,1) .';
bi = data(:,2) .';
ci = data(:,3) .';
ei = data(:,6) .';
fi = data(:,7) .';
then they will all agree in size, 1 x 6, with your 1 x 6 Pi, and you will not get the error about matrix dimensions not agreeing for .*

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