Hi,
I have 2 matrices:
A with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) defining salaries
B with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) contains either a 0 or a 1
And last I have 2 boundary values C= 2600 and D= 1700.
I want to check the following:
if B(each value) == 0 && A(each value) > C
A(this value)= C
elseif B(each value) == 1 && A(each value) > D
A(this value)= D
end
Can anyone help me out?

1 commentaire

Walter Roberson
Walter Roberson le 14 Sep 2015
There is no such thing as an "if loop". There are "for loop" and there are "while loop" and there are "if statement". A loop would have to execute its body multiple times, but "if" executes the body only 1 time or 0 times.

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 Réponse acceptée

Guillaume
Guillaume le 14 Sep 2015

0 votes

You don't need any if. Just use logical operations. Your first condition is to replace elements when B is false (i.e. B==0 or simply ~B) and A greater than C, so is simply writen as A(~B & A>C). Similarly your second condition is simply A(B==1 & A>D) (which simplifies to A(B & A>D). You just have to apply that to each cell of the cell arrays:
for cellidx = 1:numel(A)
a = A{cellidx};
b = B{cellidx};
a(~b & a>C) = C;
a(b & a>D) = D;
A{celldix} = a;
end

1 commentaire

Bas
Bas le 14 Sep 2015
Thanks Guillaume, this is what I was searching for!

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Plus de réponses (1)

Titus Edelhofer
Titus Edelhofer le 14 Sep 2015

0 votes

Hi,
I'm not 100% sure I understand what you want to do, but I guess it should be like this
for i=1:length(A)
if all(B{i}(:)==0 & A{i}(:)>C)
A{i}(:) = C;
elseif all(B{i}(:)==1 & A{i}(:)>D)
A{i}(:) = D;
end
end
Titus

4 commentaires

Bas
Bas le 14 Sep 2015
Modifié(e) : Bas le 14 Sep 2015
Hi,
thanks for your answer!
I guess this works partly, because the problem is that my matrix A consists of 1x24 cells. Each cell has a different length, i.e. A{1}= 2362x1, A{2}= 2341x1 etc. Therefore the for loop with i= 1:length(A) doesn't work well..
What I want is that none of the values in A exceed the boundary specified in either C or D, depending on the value of B, being 0 or 1 respectively.
Titus Edelhofer
Titus Edelhofer le 14 Sep 2015
length(A) is the length of the cell array. The code is (just as Guillaume's code) totally independent of the sizes of each A{i}, B{i} (of course as long as they match) :).
Titus
Guillaume
Guillaume le 14 Sep 2015
Modifié(e) : Guillaume le 14 Sep 2015
Both codes have the following preconditions:
assert(isequal(numel(A), numel(B)));
assert(all(cellfun(@(a,b) isequal(size(a), size(b)), A, B)));
Titus Edelhofer
Titus Edelhofer le 14 Sep 2015
I wish I could vote for a comment! Nice assert calls.

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